Answer:
4 trays should he prepared, if the owner wants a service level of at least 95%.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 5
Standard Deviation, σ = 1
We are given that the distribution of demand score is a bell shaped distribution that is a normal distribution.
Formula:
P(X > x) = 0.95
We have to find the value of x such that the probability is 0.95
P(X > x)
Calculation the value from standard normal z table, we have,
Hence, 4 trays should he prepared, if the owner wants a service level of at least 95%.
Use a variable, x, to stand in for the number.
5+x is less than 17.
x is less than 12
Hope this helps!
Use Multiplication Distribute Property: (xy)^a = x^ay^a
6^2(x^-2)^2(0.5x)^4
Simplify 6^2 to 36
36(x^-2)^2(0.5x)^4
Use this rule: (x^a)^b = x^ab
36x^-4(0.5x)^4
Use the Negative Power Rule: x^-a = 1/x^a
36 × 1/x^4(0.5x)^4
Use the Multiplication Distributive Property: (xy)^a = x^ay^a
36 × 1/x^4 × 0.5^4x^4
Simplify 0.5^4 to 0.0625
36 × 1/x^4 × 0.0625x^4
Simplify
2.25x^4/x^4
Cancel x^4
<u>2.25</u>
No, 1/3 is greater than 1/6.
1/3 converts to 2/6.
2/6 > 1/6
Answer:
irrational, not a perfect square.
Step-by-step explanation:
