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KATRIN_1 [288]
2 years ago
6

Can you tell me the ones I got wrong and which are the correct ones. Might need to zoom in. Will give brainly

Mathematics
1 answer:
Mama L [17]2 years ago
7 0

Answer:

I think

Step-by-step explanation:

y might be 50 degrees

z might be 40 degrees

w might be 140 degrees

x might be 130 degrees

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It takes Bill 1/10 hour to walk a 1/6 mile park loop. What is Bill's unit rate, in miles per hour?
marta [7]

Answer:

.60

Step-by-step explanation:

You trying to divide them and you have to do KCF (Keep, Change, Flip) You keep the 1/10, you change the division sign into a multiplication sign, you then flip the 1/6 to 6/1. Now you multiple and you get your answer!

6 0
2 years ago
A regular hexagon is dilated by a scale factor of 75 to create a new hexagon. How does the perimeter of the new hexagon compare
mezya [45]
Let the length of the original hexagon be x:
the perimeter of the hexagon will be:
P=length*number of sides
P=6*x=6x
After the dilation the new length became:
length=scale factor × original length
=75 × x
=75x
thus the new perimeter will be:
6×75x
=450x
hence the new perimeter compared to the old one will be:
450x/6x
=75
the new perimeter is 75 times the old one
3 0
3 years ago
Read 2 more answers
Two bicyclist started racing towards each other when they were 98 miles apart. Three hours later they did not yet meet and the d
JulsSmile [24]

Answer:

I think its 32.6 but if i was you i would wait a little for other people to answer just in case

6 0
3 years ago
Please help me on this!
Mumz [18]

Answer:

C. -0.97

Step-by-step explanation:

that is the approximate correlation coefficient

6 0
2 years ago
Two pools are being filled with water. To start, the first pool had 1850 liters of water and the second pool had 1334 liters of
prohojiy [21]

Answer:

a)Total amount of water in pool 1 after x minutes = 1850+27x

Total amount of water in pool 2 after x minutes = 1334+39x

b) an equation to show when the two pools would have the same amount of water is 1850+27x= 1334+39x

Step-by-step explanation:

First Pool :

Initial amount of water in Pool = 1850 liters

Water is being added to the first pool at a rate of 27 liters per minute.

Amount of water added after x minutes = 27x

So, Total amount of water after x minutes = 1850+27x

Second Pool:

Initial amount of water in Pool = 1334 liters

Water is being added to the first pool at a rate of 39 liters per minute.

Amount of water added after x minutes = 39x

So, Total amount of water after x minutes = 1334+39x

Now to find  an equation to show when the two pools would have the same amount of water.

1850+27x= 1334+39x

1850-1334=39x-27x

516=12x

\frac{516}{12}=x

43 =x

Hence

a)Total amount of water in pool 1 after x minutes = 1850+27x

Total amount of water in pool 2 after x minutes = 1334+39x

b) an equation to show when the two pools would have the same amount of water is 1850+27x= 1334+39x

5 0
3 years ago
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