It looks like you're asked to find the value of y(-1) given its implicit derivative,

and with initial condition y(2) = -1.
The differential equation is separable:

Integrate both sides:


Solve for y :



![y = -\dfrac1{\sqrt[3]{3x+C}}](https://tex.z-dn.net/?f=y%20%3D%20-%5Cdfrac1%7B%5Csqrt%5B3%5D%7B3x%2BC%7D%7D)
Use the initial condition to solve for C :
![y(2) = -1 \implies -1 = -\dfrac1{\sqrt[3]{3\times2+C}} \implies C = -5](https://tex.z-dn.net/?f=y%282%29%20%3D%20-1%20%5Cimplies%20-1%20%3D%20-%5Cdfrac1%7B%5Csqrt%5B3%5D%7B3%5Ctimes2%2BC%7D%7D%20%5Cimplies%20C%20%3D%20-5)
Then the particular solution to the differential equation is
![y(x) = -\dfrac1{\sqrt[3]{3x-5}}](https://tex.z-dn.net/?f=y%28x%29%20%3D%20-%5Cdfrac1%7B%5Csqrt%5B3%5D%7B3x-5%7D%7D)
and so
![y(-1) = -\dfrac1{\sqrt[3]{3\times(-1)-5}} = \boxed{\dfrac12}](https://tex.z-dn.net/?f=y%28-1%29%20%3D%20-%5Cdfrac1%7B%5Csqrt%5B3%5D%7B3%5Ctimes%28-1%29-5%7D%7D%20%3D%20%5Cboxed%7B%5Cdfrac12%7D)
Answer:
1/2
Step-by-step explanation:
There are 2 numbers less than 3. (1 and 2) and one 6 on a dice. Therefore there is a 3 out of 6 chance of rolling one of these 3 numbers (1, 2, and 6). This can be represented as 3/6 which would simplify to 1/2 or 50%.
It can also be found this way...
Probability = Number of desired outcomes ÷ number of possible outcomes. Therefore 3 ÷ 6 = 0.5 which is equal to 50% or 1/2.
I hope you choose my answer so you do well on your assignment! I've gotten an A in math every year :)
As they are similar corresponding sides are in the same ratio, so
18/15 = x / 4
x = 4*18 / 15
x = 4.8 answer
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