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White raven [17]
2 years ago
10

The length of a rectangle is three times its width.

Mathematics
1 answer:
Alborosie2 years ago
7 0

Step-by-step explanation:

2w+6w=80

w=10

l=30

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NEED HELP PLEASE BEGGING PLEASE!!!!
Sliva [168]

Answer:

-54

Step-by-step explanation:

8(-9) - 6(-3)\\

Multiply 8 by -9 and 6 by -3

-72 - (-18)

SubtractValue = -54

Hope this helps

plz mark brainliest

6 0
3 years ago
|-9c|=8 and solve for c
melisa1 [442]
C = negative 8/9 or 8/9
5 0
3 years ago
f(x) = 4x^2+2x+6f(x)=4x 2 +2x+6f, left parenthesis, x, right parenthesis, equals, 4, x, squared, plus, 2, x, plus, 6 What is the
vladimir2022 [97]

<u>Given</u>:

The given function is f(x)=4x^2+2x+6

We need to determine the value of the discriminant f and also to determine the distinct real number zeros of f.

<u>Discriminant</u>:

The discriminant can be determined using the formula,

\Delta = b^2-4ac

Now, we shall determine the discriminant of the function f(x)=4x^2+2x+6

Substituting the values in the formula, we have;

\Delta=(2)^2-4(4)(6)

\Delta=4-96

\Delta=-92

Thus, the value of the discriminant of f is -92.

<u>Distinct roots:</u>

The distinct zeros of the function f can be determined by

(1) If \Delta>0, then the function has 2 real roots.

(2) If \Delta=0, then the function has 2 real roots ( or one repeated root).

(3) If \Delta, then the function has 2 imaginary roots (or no real roots).

Since, the discriminant is \Delta=-92 \ < \ 0 , then the function has no real roots  or 2 imaginary roots.

Thus, the function has 2 imaginary roots.

4 0
3 years ago
(60 points)
natka813 [3]

Answer:

<h2>2. D. 64</h2><h2>5. B. 1, -3/2</h2><h2>6. C. 0, 2</h2>

Step-by-step explanation:

2.\\(a-b)^2=a^2-2ab+b^2\\\\x^2-16x=-8\\\\x^2-2(x)(8)=-8\\\\\text{We have}\ 2ab=2(x)(8).\ \text{Therefore}\ b=8.\\\\x^2-2(x)(8)=-8\qquad\text{add}\ 8^2=64\ \text{to both sides}\\\\x^2-2(x)(8)+8^2=-8+64\\\\(x-8)^2=56

5.\\2x^2+x-1=2\qquad\text{subtract 2 from both sides}\\\\2x^2+x-3=0\\\\2x^2+3x-2x-3=0\\\\x(2x+3)-1(2x+3)=0\\\\(2x+3)(x-1)=0\iff 2x+3=0\ \vee\ x-1=0\\\\2x+3=0\qquad\text{subtract 3 from both sides}\\2x=-3\qquad\text{divide both sides by 2}\\\boxed{x=-\dfrac{3}{2}}\\\\x-1=0\qquad\text{add 1 to both sides}\\\boxed{x=1}

6.\\2x^2-4x=0\qquad\text{divide both sides by 2}\\\\x^2-2x=0\\\\x(x-2)=0\iff x=0\ \vee\ x-2=0\\\\\boxed{x=0}\\\\x-2=0\qquad\text{add 2 to both sides}\\\boxed{x=2}

8 0
3 years ago
. <br> Solve using traditional division: 3,385 31.<br> 109 R6<br> 1009<br> 108 R 37<br> 109
dimulka [17.4K]

Answer:

109r6

Step-by-step explanationi got it

7 0
2 years ago
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