Answer:
The second time when Luiza reaches a height of 1.2 m = 2 08 s
Step-by-step explanation:
Complete Question
Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.
H(t) = -0.6 cos (2pi/2.5)t + 1.5.
What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.
Solution
Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as
H(t) = -0.6cos(2π/2.5)t + 1.5
What is t when H = 1.2 m
1.2 = -0.6cos(2π/2.5)t + 1.5
0.6cos(2π/2.5)t = 1.2 - 1.5 = -0.3
Cos (2π/2.5)t = (0.3/0.6) = 0.5
Note that in radians,
Cos (π/3) = 0.5
This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,
Cos (5π/3) = 0.5
So,
Cos (2π/2.5)t = Cos (5π/3)
(2π/2.5)t = (5π/3)
(2/2.5) × t = (5/3)
t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.
Hope this Helps!!!
By finding the scale factor, we will see that the volume of the smaller solid is 86.75 m³.
<h3>
How to get the volume of the smaller solid?</h3>
If the solids are similar, then there is a scale factor between the two. Then the relation between the areas is equal to the scale factor squared, and the relation between the volumes is equal to the scale factor cubed.
This means that if the areas are 169 m² and 81 m², then we can write:
169 m² = (k²)*81 m²
Solving for k, we get:
k = √(169 m²/81 m²) = 1.44
Then if the volume of the large solid is 124.92m³ we can write:
124.92m³ = k³*V
Replacing k and solving for V we get:
124.92m³ = (1.44)³*V
(124.92m³/ (1.44)³) = V = 86.75 m³
If you want to learn more about scale factors:
brainly.com/question/3457976
#SPJ4
<h3>
♫ - - - - - - - - - - - - - - - ~<u>
Hello There</u>
!~ - - - - - - - - - - - - - - - ♫</h3>
➷ If you think about the positioning on a number line, -3 would be the closest to 0 - making it the largest. The next largest would then be -5 and then finally -8.
As per the options, the correct one would be D
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➶ Hope This Helps You!
➶ Good Luck (:
➶ Have A Great Day ^-^
↬ ʜᴀɴɴᴀʜ ♡
