Answer:
The probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.
Step-by-step explanation:
Let the random variable <em>X</em> denote the water depths.
As the variable water depths is continuous variable, the random variable <em>X</em> follows a continuous Uniform distribution with parameters <em>a</em> = 2.00 m and <em>b</em> = 7.00 m.
The probability density function of <em>X</em> is:
Compute the probability that a randomly selected depth is between 2.25 m and 5.00 m as follows:
![=\frac{1}{5.00}\int\limits^{5.00}_{2.25} {1} \, dx\\\\=0.20\times [x]^{5.00}_{2.25} \\\\=0.20\times (5.00-2.25)\\\\=0.55](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B5.00%7D%5Cint%5Climits%5E%7B5.00%7D_%7B2.25%7D%20%7B1%7D%20%5C%2C%20dx%5C%5C%5C%5C%3D0.20%5Ctimes%20%5Bx%5D%5E%7B5.00%7D_%7B2.25%7D%20%5C%5C%5C%5C%3D0.20%5Ctimes%20%285.00-2.25%29%5C%5C%5C%5C%3D0.55)
Thus, the probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.
Answer:
6/25 km in 1 min; or 0.24 km/min
Step-by-step explanation:
The info about Angel is not necessary.
Jayden runs 3 laps in 5 mins
Each lap is 2/5 km, so Jayden runs 3 x (2/5 km) in 5 min = 6/5 km in 5 min.
Distance = rate x time
6/5 km = rate (5 min)
We want to isolate r (rate), so divide both sides by 5 min
6/5 km ÷ 5 min = r
6/5 km (1/5 min) = r
6/25 km/min = r (notice how the units worked out correctly to km/min)
So, Jayden runs 6/25 km in 1 min.
Answer: -3.75
Step-by-step explanation:
10000000000% sure because I took the test
Answer:
1st option
Step-by-step explanation:
let y = f(x) and rearrange making x the subject
y = 2x + 1 ( subtract 1 from both sides )
y - 1 = 2x ( divide both sides by 2 )
= x
Change y back into terms of x with x being the inverse h(x)
h(x) = 
= 
x -
Answer:
16.9%
Step-by-step explanation:
Let's find the answer by using the following formula:
final people=(initial people)+((initial people)*(percent increase)) which can be written as:
percent increase=((final people)-(initial people))/(initial people) so:
percent increase=(83-71)/71=0.169=16.9%
In conclusion, the percent increase is 16.9%.
