Question

Annette, Barb, and Carlita work in a clothing shop. One day the three had combined sales of $1480. Annette sold $120 more than Barb. Barb and Carlita combined sold $280 more than Annette. Write and solve a linear system to find out how much did each person sold.

Answer 1

Answer:

The quantity sold by Annette was $600

The quantity sold by Barb was $480

The quantity sold by Carlita was $400

Step-by-step explanation:

Let

x ----> quantity sold by Annette

y ---> quantity sold by Barb

z ---> quantity sold by Carlita

we know that

$x+y+z=1,480$ ----> equation A

$x=y+120$ ----> equation B

$y+z=x+280$ ----> equation C

substitute equation C in equation A and solve for x

$x+(x+280)=1,480$

$2x=1,480-280$

$2x=1,200$

$x=\ 600$

Find the value of y

$x=y+120$

$600=y+120$

$y=600-120=\ 480$

Find the value of z

$x+y+z=1,480$

$600+480+z=1,480$

$1,080+z=1,480$

$z=\ 400$

therefore

The quantity sold by Annette was $600

The quantity sold by Barb was $480

The quantity sold by Carlita was $400