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Westkost [7]
3 years ago
11

What's ∣x−2∣=∣4+x∣????

Mathematics
1 answer:
LuckyWell [14K]3 years ago
7 0

Answer:

in the chapter 7 in class 9 Ex 7.3

one time -  and second time +

Step-by-step explanation:

x-2=4+x

1) x-2=-(4+x)

  x-2=-4-x

  x+x=-4+2

  2x=-2

  x=-2/2

  x=-1

2) x-2=4+x

   =0

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Evaluating expressions for the value of x 4.5x-12 x=2
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A soccer ball is kicked from 3 feet above the ground. the height,h, in feet of the ball after t seconds is given by the function
dexar [7]
Here's our equation.

h=-16t+64t+3

We want to find out when it returns to ground level (h = 0)

To find this out, we can plug in 0 and solve for t.

0 = -16t+64t+3 \\ 16t-64t-3=0 \\ use\ the\ quadratic\ formula\ \frac{-b\±\sqrt{b^2-4ac}}{2a}  \\ \frac{-(-64)\±\sqrt{(-64)^2-4(16)(-3)}}{2*16}  = \frac{64\±\sqrt{4096+192}}{32}

= \frac{64\±\sqrt{4288}}{32} = \frac{64\±8\sqrt{67}}{32} = \frac{8\±\sqrt{67}}{4} = \boxed{\frac{8+\sqrt{67}}{4}\ or\ 2-\frac{\sqrt{67}}{4}}

So the ball will return to the ground at the positive value of \boxed{\frac{8+\sqrt{67}}{4}} seconds.

What about the vertex? Simple! Since all parabolas are symmetrical, we can just take the average between our two answers from above to find t at the vertex and then plug it in to find h!

\frac{1}2(\frac{8+\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(2+\frac{\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(4) = 2

h=-16t^2+64t+3 \\ h=-16(2)^2+64(2)+3 \\ \boxed{h=67}


8 0
3 years ago
Find the range of y = -3x + 7 for the domain {-8, -6, -3, -2, 2}
svetlana [45]
The domain is the set of x-values of a function. The range is the set of y-values of a function.

You are told that the domain, or x-values, are -8, -6, -3, -2, and 2. To find the range, you just need to plug in each of the x-values into the function <span>y = -3x + 7 and find the value of y.
1) When x = -8:
</span><span>y = -3x + 7
y = -3(-8) + 7
y = 24 + 7
y = 31

2) When x = -6
</span>y = -3x + 7
y = -3(-6) + 7
y = 18 + 7
y = 25

3) When x = -3
y = -3x + 7
y = -3(-3) + 7
y = 9 + 7
y = 16

4) When x = -2
y = -3x + 7
y = -3(-2) + 7
y = 6 + 7
y = 13

5) When y = 2
y = -3x + 7
y = -3(2) + 7
y = -6 + 7
y = 1

The range is {31, 25, 16, 13, 1}.

-------

Answer: 
{31, 25, 16, 13, 1}
5 0
3 years ago
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