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marishachu [46]
3 years ago
9

SOS HELP ASAP

Mathematics
1 answer:
Nitella [24]3 years ago
7 0

Answer:

The answer would be C

Step-by-step explanation:

The only logical reason would be positive because the parabola is opening up. The average rte of change is opening 0.5 per square

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14 mm<br> 29 mm<br> Calculate the surface area.
tino4ka555 [31]

Answer:

14x29=406 2hich would be the area

Step-by-step explanation:

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What is 4 over 10 in simplest form
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Ok so find 1's

remember that 4/4=1 also x/x=1 those are ones
also remember
if you had
10/30 that equals 10/10 times 1/3=1 times 1/3

so find ones

4/10=2/2 times 2/5=1 times 2/5=2/5
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3 years ago
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Write in slope-intercept form an equation of a line that passes through the given points. (1,6) and (3,2)
Nataliya [291]

Answer:

The answer to your proble I'm slow intercept from is y=-2x+8

Step-by-step explanation:

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3 years ago
A pony, tied to the end of a lead, can walk in a full circle, a distance of 56.55 meters. About how long is its lead?
sergejj [24]
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​Find all roots: x^3 + 7x^2 + 12x = 0 <br> Show all work and check your answer.
Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

<u>Solution:</u>

We have been given a cubic polynomial.

x^{3}+7 x^{2}+12 x=0

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

x^{3}+7 x^{2}+12 x=0

x\left(x^{2}+7 x+12\right)=0   ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

x^{2}+7 x+12=0

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}

<em><u>Therefore, the two roots are:</u></em>

\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}

And,

\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0
3 years ago
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