Answer:
x = 50
m∠D = 150°
m∠F = 30°
Step-by-step explanation:
- supplementary angles are two angles whose sum is 180°
∠D + ∠F = 180°
3x + x - 20 = 180
3x + x = 180 + 20
4x = 200
x = 200/4
x = 50
D = 3*50 = 150
∠D = 150°
F = 50 - 20 = 30
∠F = 30°
Answer:
-11/2
Step-by-step explanation:
because that's the answer
Option D:
ΔCAN ≅ ΔWNA by SAS congruence rule.
Solution:
Given data:
m∠CNA = m∠WAN and CN = WA
To prove that ΔCAN ≅ ΔWNA:
In ΔCAN and ΔWNA,
CN = WA (given side)
∠CNA = ∠WAN (given angle)
NA = NA (reflexive side)
Therefore, ΔCAN ≅ ΔWNA by SAS congruence rule.
Hence option D is the correct answer.
Answer:
x value of vertical asymptote and y value of horizontal asymptote
Step-by-step explanation:
The graph of 1/x approaches infinity as x approaches 0 (the vertical asymptote)
As x gets either bigger or smaller, 1/x approaches the x-axis (from above on the positive side, from below on the negative side) (the horizontal asymptote)
Consider 1/(x-5) + 2, at what value of x does the graph 'go nuts' ?
When the bottom of the fraction becomes 0, x - 5 becomes 0 when x = 5, so the vertical asymptote of g(x) is at x=5
What value of y does f(x) approach as x gets more positive or more negative - as x gets bigger (as an example), y approaches 0
What y value does g(x) approach as x gets bigger? Well, as x gets big, 1/(x-5) gets small, approaching 0. The smallest 0 + 2 can get is 2, so y=2 is the horizontal asymptote
Answer:
the answer is B. (15,4) :
Step-by-step explanation:
