Answer:
Step-by-step explanation:
Given problems are absolute value problems, So we need to plug the values of given parameters and get the final result.
We have given here,
a =-2 , b = 3 , c = -4 and d = -6
Now we know that An absolute function always gives a positive value.
Let's apply this strategy in the given problems.
1. ║a+b║
Plug a= -2 and b = 3
We get, ║-2+3║=║1║= 1
2. 5║c+b║
Plug c= -4 and b=3
i.e. 5║-4 + 3║= 5║-1║=5×1 = 5
3. a+b║c║
Plug values a= -2 , b=3 and c=-4
i.e -2 +3║-4║ = -2 + 3×4 = -2 + 12 = 10
4. ║a+c║÷(-d)
i.e ║-2 + (-4)║÷(-6) = ║-6║÷(-6) = 6÷(-6) = -1
5. 3║a+d║+b
i.e 3║-2+(-6)║+3 = 3║-8║+3 = 3×8 +3 = 27
Answer:
-1.9
Step-by-step explanation:
I rounded it to the tenth
7/8 * cm/ month * 5 months =
35/8 cm
4 3/8 cm
Answer: 4 3/8 cm
Question is Incomplete, Complete question is given below.
Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.
Answer:
∆ABC is right angled triangle with right angle at B.
Step-by-step explanation:
Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.
We need to prove that triangle is the right angled triangle.
Let the triangle be denoted by Δ ABC with side as;
AB = (a - 1) cm
BC = (2√ a) cm
CA = (a + 1) cm
Hence,
Now We know that

So;


Now;

Also;

Now We know that




[By Pythagoras theorem]

Hence, 
Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.
This proves that ∆ABC is right angled triangle with right angle at B.