if f is a second degree polynomial function such that f(3) = 5, f' (3) = 6, and f'' (3) = 4, what is the value of f(2)
1 answer:
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This is the graph, on the x and y axis od the graph you plot the point at 4 (positive)
Answer:
Step-by-step explanation:
The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.
×
+
×
Complete the multiplication and the equation becomes
The two fractions now have like denominators so you can add the numerators.
This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 14 and 12 using
GCF(14,12) = 2
14÷2 / 12÷2 =7/6
The fraction
7/6
is the same as
7÷6
Convert to a mixed number using
long division for 7 ÷ 6 = 1R1, so
7/6=
Therefore:
3/4 − (−5/12) =
Solution by Formulas
Apply the fractions formula for subtraction, to
3/4 − (−5/12)
and solve
(3×12) − (−5×4) 4×12
=3/6− (−20/48)
=56/48
Reduce by dividing both the numerator and denominator by the Greatest Common Factor GCF( 56,48) = 8
56÷8 / 48÷8 =7/6
Convert to a mixed number using
long division for 7 ÷ 6 = 1R1, so
7/6=
Therefore:
3/4 − (-5/12) =
- Factor the indicated expression:
- Simplified the index, the root and also the exponent using the number 2.