if f is a second degree polynomial function such that f(3) = 5, f' (3) = 6, and f'' (3) = 4, what is the value of f(2)

Mathematics

1 answer:

insens350 [35]3 years ago

6 0

Answer:

that is the true answer..

good luck

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3 times the complement of an angle is 30 more than the supplement of the original angle. What is the measure of the angle? 15° 3

labwork [276]

1. By definition, the sum of the Suplementary angles is 180° and the sum of the Complementary angles is 90°. Keeping this on mind, you have:

90-x (The complement of the angle)
180-x (The sumplement of the angle)

"x" is the angle that you want to calculate.

2. Then, you have:

3(90-x)+30=180-x
(270-3x)+30=180-x
300-3x=180-x
300-180=-x+3x
120=2x
120/2=x
x=60°
<span>
What is the measure of the angle?</span>

The answer is: The measure of the angle is 60°.

6 0

3 years ago

Select and use the most direct method to solve 2x(x + 1.5) = -1. Describe and justify the methods you used to solve the quadrati

miskamm [114]

Step-by-step explanation:

Given that,

A quadratic equation,

2x(x + 1.5) = -1

We need to solve the quadratic equation. Firstly we need to simplify the above equation to form it as $ax^2+bx+c=0$ .

So,

$2x^2+3x=-1\\\\2x^2+3x+1=0$

Here, a = 2, b = 3 and c = 1

The roots of the given equation can be given by :

$x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

Putting all the values we get :

$x=\dfrac{-b\pm \sqrt{b^2+4ac} }{2a}, \dfrac{-b\pm \sqrt{b^2-4ac} }{2a}\\\\x=\dfrac{-3\pm \sqrt{3^2+4(2)(1)} }{2(2)}, \dfrac{-3\pm \sqrt{3^2-4(2)(1)} }{2(2)}\\\\x=\dfrac{-3+1}{4}, \dfrac{-3-1}{4}\\\\x=-\dfrac{1}{2}, -1$