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Mashutka [201]
3 years ago
10

Fine the slope of the line perpendicular to Y=-1/2x -2

Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
7 0

\text{Let}\\\\k:y=m_1x+b_1\ \text{and}\ l:y=m_2x+b_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\\text{We have}\ k:y=-\dfrac{1}{2}x-2\to m_1=-\dfrac{1}{2}.\\\\\text{Therefore the slope of the line}\ l\ \text{perpendicular to the line}\ k\ \text{is:}\\\\m_2=-\dfrac{1}{-\frac{1}{2}}=\dfrac{1}{\frac{1}{2}}=2\\\\Answer:\ \boxed{slope=2}

makkiz [27]3 years ago
5 0

Answer:

perpendicular slope = 2

Step-by-step explanation:

the equation of a line in slope-intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = - \frac{1}{2} x - 2 is in this form

with slope m = - \frac{1}{2}

given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{-1/2} = 2


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oceanside bike shop charges an $11 fee to all customers plus $8 an hour for renting a bike. Joan paid $75 at the end of her bike
romanna [79]

Answer:

8 hours

Step-by-step explanation:

Subtract the initial fee from the total cost

75-11 = 64

Divide the hourly rate by the cost after the fee

\frac{64}{8} = 8

Joan rented the bike for 8 hours

8 0
4 years ago
Which equation is always true?
madreJ [45]

Answer:

4).

Step-by-step explanation:

sin A = cos B

Because sin A = CB/AB and cos B = CB/AB.

5 0
4 years ago
Write an equation of the line containing the point (3,5) and perpendicular to the line 4x-3y=5
ICE Princess25 [194]

Answer:

Step-by-step explanation:

In order to write the equation of the line perpendicular to the given line, we first have to know what the slope of the given line is, and there's no way to tell by looking at it in its current form, which is standard. We need to solve that equation for y to determine the slope of that line. Solving for y:

-3y=-4x+5 and

3y = 4x - 5 (just change all the signs so our y term isn't negative anymore...yes, you're "allowed" to do that!) and

y=\frac{4}{3}x-\frac{5}{3} So we can see now that the slope of this line is 4/3. That means that the perpendicular slope is -3/4. Passing through the given point (3, 5):

y-5=-\frac{3}{4}(x-3)* and

y-5=-\frac{3}{4}x+\frac{9}{4} and

y=-\frac{3}{4}x+\frac{9}{4}+\frac{20}{4} so

y=-\frac{3}{4}x+\frac{29}{4}** and, in standard form:

4y = -3x + 29 and

3x + 4y = 29***

* : point-slope form

** : slope-intercept form

*** : standard form

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Step-by-step explanation:

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3 years ago
Given the points (2,k) and (0,−6), for which values of k would the distance between the points be 5–√ ?
natka813 [3]

The value of k are -5 and -7 if the distance between points (2,k) and (0,−6) is √5

<h3>What is a distance formula?</h3>

It is defined as the formula for finding the distance between two points. It has given the shortest path distance between two points.

The distance formula can be given as:

\rm d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The question is:

Given the points (2,k) and (0,−6), for which values of k would the distance between the points be √5

\rm \sqrt{5}=\sqrt{(0-2)^2+(-6-k)^2}

5 = 4 + (6 + k)²

After solving:

\rm 4+\left(6+k\right)^2-4=5-4

(6 + k)² = 1

k = -5 or -7

Thus, the value of k are -5 and -7 if the distance between points (2,k) and (0,−6) is √5

Learn more about the distance formula here:

brainly.com/question/18296211

#SPJ1

8 0
2 years ago
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