Let the initial point of the vector be (x,y). Then the magnitude of the vector v can be written as:
The magnitude of vecor v is given to be 10. So we can write:
Now from the given options, we have to check which one satisfies the above equation. That point will be the initial point of the vector.
The point in option d, satisfies the equation.
Thus, the answer to this question is option D
I Think The answer is a I hope it helps My friend Message Me if I’m wrong and I’ll change My answer and fix it for you
1. 4x - 8 + 2x + (-5x) + x^2 - 3 = 4x - 8 + 2x - 5x + x^2 - 3...now, we just combine like terms....lets group them...it will be easier ...x^2 + (4x + 2x - 5x ) - 8 - 3 = x^2 + x - 11
2. 2x + 5x = 8x
3. 2r + 4 + 3x - 2 = 3x + 2r + (4 - 2) = 3x + 2r + 2
4. 3x - 2y - x + 5y = (3x - x) + (5y - 2y) = 2x + 3y
5. 2y^2 - 8y^3 + 5y - 5y^2 + 4y^3 = (4y^3 - 8y^3) + (2y^2 - 5y^2) + 5y =
-4y^3 - 3y^2 + 5y
Answer : 12312
Step-by-step explanation : According to BODMAS, Addition (+) comes first
Hence -- 9 + 19 + 12 + 12323 = 12363
12363 - 12 - 39 = 12363 - 51
= 12312
Answer:
596.34m approx
Step-by-step explanation:
Given data
Let the Starting point be x
A helicopter flew north 325 meters from x
Then flew east 500 meters
Let us apply the Pythagoras theorem to solve for the resultant which is the distance from the starting position
x^2= 325^2+500^2
x^2=105625+250000
x^2= 355625
x= √355625
x=596.34m
Hence the distance from the starting point is 596.34m approx
