Question

Is f(x)=4x^2-x+1 then f(a+1) equals

Answer 1

Answer:

$f(a + 1) = 4 {a}^{2} + 7a + 4$

Step-by-step explanation:

$f(x) = 4 {x}^{2} - x + 1$

substitute...

change x with a+1. In other words...

$f(a + 1) = 4 {(a + 1)}^{2} - (a + 1) + 1 \\ = 4( {a}^{2} + 2a + 1) - a - 1 + 1 \\ = 4 {a}^{2} + 8a + 4 - a \\ = 4 {a}^{2} + 7a + 4$