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guajiro [1.7K]
3 years ago
9

#1. 6k+8=-10 #2. 5z-5=15 I need to solve k and z

Mathematics
1 answer:
MAVERICK [17]3 years ago
7 0

Answer:

1. k= 6

2. z= 4

Step-by-step explanation:

1. Given equation is:

6k+8=-10

We will solve the equation.

Subtracting 8 from both sides

6k+8-8 = -10-8

6k = -18

Dividing both sides by 6

\frac{6k}{6}=\frac{-18}{6}\\k=-3

2. Given equation is:

5z-5=15

We will solve the equation.

Adding 5 on both sides

5z-5+5=15+5

5z=20

Dividing both sides by 5

\frac{5z}{5}=\frac{20}{5}\\z=4

Hence,

1. k= 6

2. z= 4

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3 years ago
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\large\boxed{B)\ -2}

Step-by-step explanation:

\left\{\begin{array}{ccc}3(x+y)=12&(1)\\\\\dfrac{x}{2}=3&(2)\end{array}\right\\\\(2)\ \dfrac{x}{2}=3\qquad\text{multiply both sides by 2}\\\\2\!\!\!\!\diagup^1\cdot\dfrac{x}{2\!\!\!\!\diagup_1}=(2)(3)\\\\x=6\\\\\text{Put it to (1):}\\\\3(6+y)=12\qquad\text{divide both sides by 3}\\\\\dfrac{3\!\!\!\!\diagup^1(6+y)}{3\!\!\!\!\diagup_1}=\dfrac{12}{3}\\\\6+y=4\qquad\text{subtract 6 from both sides}\\\\6-6+y=4-6\\\\y=-2

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