Answer:
c
Step-by-step explanation:
The equation =( denominater * derivative of numerator - numerator * derivative of denominator) / denominator ^2
so the qstn is (x^2 + 3x +2) / (x+3)
apply the values as the above eqtn states
ie,[ (x+3) * derivative of (x^2 +3x + 2)] - [( x^2 +3x + 2) *derivative of (x+3)] /
(x+3)^2
derivative of numerator, (x^2 +3x + 2) is 2x+3
" of denominator, (x+3) is 1
so we get
[(x+3)* (2x + 3 ) - (x^2 +3x + 2) *1 ] / (x+3)^2
open the brackets
[ 2x^2 + 3x + 6x + 9 - x^2 +3x + 2 ] / (x+3)^2
subtract similar terms and we get the final answer in option c
