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suter [353]
3 years ago
14

Rosa read 57 pagesof a book in the morning she read 13 fewer pegues in the afternoon how many pages dd rosa read in the afternoo

n
Mathematics
1 answer:
Allushta [10]3 years ago
3 0

In the afternoon Rosa read 13 fewer pages as compared to the number of pages read in the morning


So we subtract 13 from 57 to get the number of pages read in the afternoon.


That is the number of pages read is the afternoon=57-13=44


Therefore Rosa read 44 papers in the afternoon


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A random sample of 25 statistics examinations was selected. The average score in the sample was 76 with a variance of 144. Assum
ki77a [65]

Answer:

The confidence interval is from 69.82 o 82.18

Step-by-step explanation:

Using this formula X ± Z (s/√n)

Where

X = 76 --------------------------Mean

S = Standard Deviation

If Variance = 144

S = √144

S = 12

n = 25 ----------------------------------Number of observation

Z = 2.576 ------------------------------The chosen Z-value from the confidence table below

Confidence Interval || Z

80%. || 1.282

85% || 1.440

90%. || 1.645

95%. || 1.960

99%. || 2.576

99.5%. || 2.807

99.9%. || 3.291

Substituting these values in the formula

Confidence Interval (CI) = 76 ± 2.576 (12/√25)

CI = 76 ± 2.576(12/5)

CI = 76 ± 2.576(2.4)

CI = 76 ± 6.1824

CI = 76 + 6.1824 ~ 76 - 6.1824

CI = 82.1824 ~ 69.8176

CI = 82.18 ~ 69.82

In other words the confidence interval is from 69.8176 to 82.1824

4 0
3 years ago
PLZ HELP AND ILL GIVE BRAINLIST TO THE CORRECT ANSWER
Ivenika [448]

Answer:

I'm a little confused on what is being asked to do.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The width of a rectangle is the length minus 2 units. The area of the rectangle is 48 units. What is the width, in units, of the
ivanzaharov [21]

Answer:

6 units

Step-by-step explanation:

Remember the formula for the area of a rectangle: A = lw

What we know:

A=48

w = l-2

Substitute A for 48 and w for l-2 into the equation

A = lw

48 = l(l-2)   Use the distributive property. Multiply over the brackets.

48 = l² - 2l

Rearrange the equation to standard form (0 = ax² + bx + c) to use quadratic formula.

0 = l² - 2l - 48

a = 1 ; b = -2 ; c = -48   State the variables for the quadratic formula

Substitute a, b and c to find the length:

l = \frac{-b± \sqrt{b^{2}-4ac} }{2a}

l = \frac{-(-2)± \sqrt{(-2)^{2}-4(1)(-48)} }{2(1)}  Simplify

l = \frac{2± \sqrt{4-(-192)} }{2}

l = \frac{2± \sqrt{196} }{2}

l = \frac{2± 14 }{2}  

Split the equation at the ± for adding and subtracting. Then decide which answer is correct, or if both of them are possible answers.

l = \frac{2- 14 }{2}

l = \frac{-12 }{2}

l = -8   This is "inadmissable", or impossible because the length can't be a negative value.

l = \frac{2+ 14 }{2}

l = \frac{16 }{2}

l = 8  Length of the rectangle

Use the formula for the area of a rectangle

Substitute the length and area, then isolate "w" for the width

A = lw

48 = (8)w

48/8 = w

w = 6

Therefore the length of the rectangle is 6 units.

7 0
4 years ago
Determine the slope of the line that passes through the points (0, -5) and (-6, 6).
melamori03 [73]

Hello there,


Slope:

6 - (-5) / -6 - 0

11/-6

<em>Slope=</em> -11/6


<em>Slope intercept form: </em>y = mx + b

-5 = -11/6(0) + b

-5 = b


Answer: y = -11/6x - 5


Hope I Helped!

-Char

7 0
3 years ago
Read 2 more answers
On one of its routes across Asia, Alpha Airlines flies an aircraft with checked-in luggage capacity of 8500 lbs. There are 121 s
Doss [256]

Answer:

the probability is P=0.012 (1.2%)

Step-by-step explanation:

for the random variable X= weight of checked-in luggage, then if X is approximately normal . then the random variable X₂ = weight of N checked-in luggage = ∑ Xi  , distributes normally according to the central limit theorem.

Its expected value will be:

μ₂ = ∑ E(Xi) = N*E(Xi) = 121 seats * 68 lbs/seat = 8228 lbs

for N= 121 seats and E(Xi) = 68 lbs/person* 1 person/seat = 68 lbs/seat

the variance will be

σ₂² = ∑ σ² (Xi)= N*σ²(Xi) → σ₂ = σ *√N = 11 lbs/seat *√121 seats = 121 Lbs

then the standard random variable Z

Z= (X₂- μ₂)/σ₂ =

Zlimit= (8500 Lbs - 8228 lbs)/121 Lbs = 2.248

P(Z > 2.248) = 1- P(Z ≤ 2.248) = 1 - 0.988 = 0.012

P(Z > 2.248)= 0.012

then the probability that on a randomly selected full flight, the checked-in luggage capacity will be exceeded is P(Z > 2.248)= 0.012 (1.2%)

8 0
3 years ago
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