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UNO [17]
3 years ago
7

Evaliate - y^- 2xywhen x=- 5 and y=3

Mathematics
1 answer:
astraxan [27]3 years ago
5 0
39.
-3^ - 2(-5)(3)
-3*-3= 9
2*-5*3 = -30
9 - (-30)
subtracting a negative really means add.
9 + 30 = 39
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Hershel is designing a square pyramid that needs to have a lateral surface of 440 in². The area of the base is 121 in². Find the
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Answer:

The length of the slant height of the square pyramid is 20 in.

Step-by-step explanation:

The lateral surface area of a regular pyramid is the sum of the areas of its lateral faces.

The general formula for the lateral surface area of a regular pyramid is

                                                     A=\frac{1}{2}pl

where p represents the perimeter of the base and l the slant height.

From the information given we know that:

  • The lateral surface area of a square pyramid is 440 in².
  • The area of the base is 121 in².

And we want to find the the slant height of the pyramid.

For this, we also need to know that the area of a square is given by A=s^2, where <em>s</em> is the length of any side and the perimeter of a square is given by p=4s.

Applying the formula for the area of a square we can find the length of the side

121=s^2\\s^2=121\\s=\sqrt{121}=11

The perimeter of the base is

p=4\cdot(11)=44

Next, we can apply the formula for the lateral surface area and solve for l the slant height.

440=\frac{1}{2}44l\\\\\frac{1}{2}\cdot \:44l=440\\\\22l=440\\\\l=20

The length of the slant height of the square pyramid is 20 in.

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