Answer:
Mark got 13 more points than Nick did
Step-by-step explanation:
Mark's score in all was: 487
Nick's score in all was: 474
Answer:
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Answer and Explanation:
A function is said to be increasing, if the derivative of function is f’(x) > 0 on each point. A function is said to be decreasing if f”(x) < 0.
Let y = v (z) be differentiable on the interval (a, b). If two points z1 and z2 belongs to the interval (a, b) such that z1 < z2, then v (z1) ≤ v (z2), the function is increasing in this interval.
Similarly, the function y = v(z) is said to be decreasing, when it is differentiable on the interval (a , b).
Two points z1 and z2 Є (a, b) such that z1 > z2, then v (z1) ≥ v(z2). The function is decreasing on this interval.
The function y = v (z)
The derivative of function Y’ = v’(z) is positive, then the function is increasing.
The function y = v (z)
The derivative of function y’ is negative, then the function is decreasing.
Answer:
∠ 2 = 60°
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180°
Subtract the sum of the given angles fro 180° for ∠ 2, that is
∠ 2 = 180° - (57 + 63)° = 180° - 120° = 60°
For this case we have the following expression:

For power properties we have:

Rewriting the exponents of the expression we have:



Using the cubic root we have:
![(\frac{1}{\sqrt[3]{8^2}} a^2)](https://tex.z-dn.net/?f=%20%28%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7B8%5E2%7D%7D%20a%5E2%29%20%20%20)
![(\frac{1}{\sqrt[3]{64}} a^2)](https://tex.z-dn.net/?f=%20%28%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7B64%7D%7D%20a%5E2%29%20%20%20)
![(\frac{1}{\sqrt[3]{4^3}} a^2)](https://tex.z-dn.net/?f=%20%28%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7B4%5E3%7D%7D%20a%5E2%29%20%20%20)
Simplifying the expression we have:

Answer:
The equivalent expression is given by:
