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Paha777 [63]
3 years ago
10

I really need help !!! Will MARK BRAINLIEST!!!

Mathematics
2 answers:
bezimeni [28]3 years ago
4 0
I think it might be c. 0.020. As far as I remeber, I think that was the answer
labwork [276]3 years ago
4 0
3^2-0.1/144=
9-0.1/144=
8.9/144=
0.0618=
0.062
Your answer is D
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Slav-nsk [51]
The answer is <span>-(3/4) and 3/4</span>
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3 years ago
How would you write y=2/3x+1/3 in point slope form??
gladu [14]

Answer:

y - 1 = 2/3(x - 1).

Step-by-step explanation:

Point slope form is y - y1 = m(x - x1) where m = the slope and (x1, y1) is a point on the line.

y = 2/3x + 1/3   which gives the slope m = 2/3.

We can now find a point on the line by putting x = 1 say then find y:

y  = 2/3(1) + 1/3  =  2/3 + 1/3 = 1 so  the point is (1, 1).

(x1, y1) = (1, 1)

So the answer is ;

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3 years ago
Some researchers have conjectured that stem-pitting disease in peach-tree seedlings might be controlled with weed and soil treat
stiks02 [169]

Answer:

Part A

b. 14.6 ± 7.38

Part B

b. 3.43

Part C

a. P-value < 0.01

Part D

b. There is sufficient evidence to reject the null hypothesis

Step-by-step explanation:

Part A

The given data are;

The number of seedlings in the field = 20

The number of seedlings selected to receive herbicide A = 10

The number of seedlings selected to receive herbicide B = 10

The height in centimeters of seedlings treated with Herbicide A, \overline x _1 = 94.5 cm

The standard deviation, s₁ = 10 cm

The height in centimeters of seedlings treated with Herbicide B, \overline x _2 = 109.1 cm

The standard deviation, s₂ = 9 cm

The 90% confidence interval for μ₂ - μ₁, is given as follows;

\left (\bar{x}_{2}- \bar{x}_{1}  \right )\pm t_{\alpha /2}\sqrt{\dfrac{s_{1}^{2}}{n_{1}}+\dfrac{s_{2}^{2}}{n_{2}}}

The critical-t at 95% and n₁ + n₂ - 2 degrees of freedom is given as follows;

The degrees of freedom, df = n₁ + n₂ - 2 = 10 + 10 - 2 = 18

α = 100% - 90% = 10%

∴ For two tailed test, we have, α/2 = 10%/2 = 5% = 0.05

t_{(0.025, \, 18)} = 1.734

C.I. = \left (109.1- 94.5 \right )\pm 1.734 \times \sqrt{\dfrac{10^{2}}{10}+\dfrac{9^{2}}{10}}

C.I. ≈ 14.6 ± 7.37714603353

The 90% C.I. ≈ 14.6 ± 7.38

b. 14.6 ± 7.38

Part B

With the hypotheses are given as follows;

H₀; μ₂ - μ₁ = 0

Hₐ; μ₂ - μ₁ ≠ 0

The two sample t-statistic is given as follows;

t=\dfrac{(\bar{x}_{2}-\bar{x}_{1})}{\sqrt{\dfrac{s_{1}^{2} }{n_{1}}+\dfrac{s _{2}^{2}}{n_{2}}}}

t-statistic=\dfrac{(109.1-94.5)}{\sqrt{\dfrac{10^{2} }{10}+\dfrac{9^{2}}{10}}} \approx 3.43173361147

The two sample t-statistic ≈ 3.43

b. 3.43

Part C

From the t-table, the p-value, we have, the p-value < 0.01

a. P-value < 0.01

Part D

Given that a significance level of 0.05 level is used and the p-value of 0.01 is less than the significance level, there is enough statistical evidence to reject the null hypothesis

b. There is sufficient evidence to reject the null hypothesis.

4 0
3 years ago
Is .277277277 irrational
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4 0
3 years ago
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m_a_m_a [10]
The graph is translates down 135 units, because you can see how the y-intercept decreased by 135 units from f(x) to g(x).
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3 years ago
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