802.11n can function in "mixed mode" on the 2.4 GHz frequency, with a theoretical maximum speed of 300 Mbps, or on the 5 GHz frequency.
<h3>
What do you mean by frequency?</h3>
In the case of electrical current, frequency is the number of times a sine wave repeats or completes, a positive-to-negative cycle.
802.11n can operate in "mixed mode" on the 2.4 GHz frequency, which will support just 802.11b or 802.11g-capable systems but will slow the entire network down to the maximum speed of the earliest standard connected, at a theoretical maximum speed of 300 Mbps.
Learn more about the single-link network:
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Magnetic north is the north a compass points in the direction of. True north, on the other hand, is north based on the earth's axis.
Answer:
Option A, B, and D.
Explanation:
In the above question, the some details of the question are missing that is the part of the question.
Information Security applies to the mechanisms and techniques built and maintained to secure print, computerized, or any other type of personal, secret and confidential information or records from unauthorized access, usage, exploitation, release, damage, manipulation, or disturbance.
So, the following are the option that is true about the scenario.
Other option is not true about the scenario because Option C the click fraud are not the part or protect from the information security and Option F is not considered to the following scenario.
Answer:
t= 8.7*10⁻⁴ sec.
Explanation:
If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.
As this is not possible, (the maximum speed of interactions in the universe is equal to the speed of light), there will be a finite propagation delay.
Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:

If we choose x₀ = 0 and t₀ =0, and replace v= 2.3*10⁸ m/s, and xf=2*10⁵ m, we can solve for t:

⇒ t = 8.7*10⁻⁴ sec.
Answer:
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