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worty [1.4K]
4 years ago
14

The radius of the base of a cylinder is 28 cm and its height is 48 cm. Find the surface area of the cylinder in terms of π.

Mathematics
2 answers:
nevsk [136]4 years ago
7 0

Answer:  The required surface area of the given cylinder is 4256π cm².

Step-by-step explanation:  Given that the radius of the base of a cylinder is 28 cm and its height is 48 cm.

We are to find the surface area of the cylinder in terms of π.

We know that

the SURFACE AREA of a cylinder with base radius r units and height h units is given by

S.A.=2\pi r(r+h).

For the given cylinder, we have

r = 28 cm   and   h = 48 cm.

Therefore, the surface area of the cylinder will be

S.A.\\\\=2\pi r(r+h)\\\\=2\pi \times28(28+48)\\\\=56\pi\times 76\\\\=4256\pi~\textup{cm}^2.

Thus, the required surface area of the given cylinder is 4256π cm².

yarga [219]4 years ago
4 0
Area of the bases


<span>2π<span>r2</span>=2π∗784=1568π


</span>circumference of base


<span>2πr=56π


</span>extension of the height


<span>2πr∗h=56π∗48=2688π


</span>bases plus none base surface is total surface


<span><span>1568π+2688π=4256π</span></span>
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