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3 years ago

5 examples of a linear motion in object.

1 answer:

3 0

An example of linear motion is an athlete running 100m along a straight track. Linear motion is the most basic of all motion. ... Neglecting the rotation and other motions of the Earth, an example of linear motion is the ball thrown straight up and falling back straight down.

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A5.3 1012 kg satellite is 1,800 m from another satellite that has a mass of 3.5 x 108 kg. What is the gravitational

SIZIF [17.4K]

Answer:

$F = 3.82 * 10^4N$

Explanation:

Given

Mass of satellite 1 = 5.3 * 10¹²kg

Mass of satellite 2 = 3.5 * 10⁸kg

Distance between them = 1,800 m

Required

Gravitational Force between them.

The gravitational force between them is calculated as thus;

$F = \frac{Gm_1m_2}{r^2}$

Where G = Gravitational Constant

$G = 6.67408 * 10^{-11} Nm^2/kg^2$

$m_1 = 5.3 * 10^{12}kg$

$m_2 = 3.5 * 10^8kg$

$r = 1800m$

Substituting these values in the above formula;

$F = \frac{Gm_1m_2}{r^2}$ becomes

$F = \frac{6.67408 * 10^{-11} * 5.3 * 10^{12}*3.5 * 10^8}{1800^2}$

$F = \frac{6.67408 * 5.3 * 3.5 * 10^{-11} * 10^{12} * 10^8}{1800^2}$

$F = \frac{123.804184 * 10^{9}}{3240000}$

$F = \frac{123804184000}{3240000}$

$F = 38211.1679012$

$F = 3.82 * 10^4N$ ---- Approximated

Hence the gravitational force between them is $3.82 * 10^4N$

4 0

3 years ago

Write an expression that evaluates to true if and only if the value of the integer variable workedOvertime is true.

snow_tiger [21]

Answer:

The expression of this question can be given as:

(workedOvertime == true)

Explanation:

This question explains by the following example that is written in C language can be given as:

#include <stdio.h> //header file.

int main() //main function.

{

int workedOvertime=10; //define integer variable

int true=10;

if(workedOvertime==true) //check condition.

{

printf("true.."); //true part code.

}

else

{

printf("false.."); //false part code.

}

return 0;

}

In the above example there we define a integer variable name(workedOvertime) in this variable we assign a value. And we define another variable true in that we also assign a value. then we use if-else statement that is used for checking the value. If block always execute true value.So the answer is true.and the Expression is (workedOvertime==true).

4 0

3 years ago

Suppose a host has a 1-MB file that is to be sent to another host. The file takes 1 second of CPU time to compress 50%, or 2 sec

kozerog [31]

Answer: bandwidth = 0.10 MB/s

Explanation:

Given

Total Time = Compression Time + Transmission Time

Transmission Time = RTT + (1 / Bandwidth) xTransferSize

Transmission Time = RTT + (0.50 MB / Bandwidth)

Transfer Size = 0.50 MB

Total Time = Compression Time + RTT + (0.50 MB /Bandwidth)

Total Time = 1 s + RTT + (0.50 MB / Bandwidth)

Compression Time = 1 sec

Situation B:

Total Time = Compression Time + Transmission Time

Transmission Time = RTT + (1 / Bandwidth) xTransferSize

Transmission Time = RTT + (0.40 MB / Bandwidth)

Transfer Size = 0.40 MB

Total Time = Compression Time + RTT + (0.40 MB /Bandwidth)

Total Time = 2 s + RTT + (0.40 MB / Bandwidth)

Compression Time = 2 sec

Setting the total times equal:

1 s + RTT + (0.50 MB / Bandwidth) = 2 s + RTT + (0.40 MB /Bandwidth)

As the equation is simplified, the RTT term drops out(which will be discussed later):

1 s + (0.50 MB / Bandwidth) = 2 s + (0.40 MB /Bandwidth)

Like terms are collected:

(0.50 MB / Bandwidth) - (0.40 MB / Bandwidth) = 2 s - 1s

0.10 MB / Bandwidth = 1 s

Algebra is applied:

0.10 MB / 1 s = Bandwidth

Simplify:

0.10 MB/s = Bandwidth

The bandwidth, at which the two total times are equivalent, is 0.10 MB/s, or 800 kbps.

(2) . Assume the RTT for the network connection is 200 ms.

For situtation 1:

Total Time = Compression Time + RTT + (1/Bandwidth) xTransferSize

Total Time = 1 sec + 0.200 sec + (1 / 0.10 MB/s) x 0.50 MB

Total Time = 1.2 sec + 5 sec

Total Time = 6.2 sec

For situation 2:

Total Time = Compression Time + RTT + (1/Bandwidth) xTransferSize

Total Time = 2 sec + 0.200 sec + (1 / 0.10 MB/s) x 0.40 MB

Total Time = 2.2 sec + 4 sec

Total Time = 6.2 sec

Thus, latency is not a factor.

5 0

2 years ago

It is important for security practitioners to take into consideration the __________ element when devising password security pol

N76 [4]

Answer:

The answer is "Evidence".

Explanation:

A "practitioner" is a person that has a specific practice or specialty directly involved. A safety professional of data is indeed another who engages in the protection of data.

Evidence is used in the course of the investigation to show certain material information or characteristics of a felony. Most people seem to believe that proof is just tangible, verbal evidence.

4 0

3 years ago

How can you create an illusion of spatial depth in a two-dimensional design?

astraxan [27]

Answer:

Using three or more vanishing points within a work to create the illusion of space on a two-dimensional surface.

Explanation:

6 0

2 years ago