Every finger has a key it should be resting on when you are not typing 1. False 2. True
2 answers:
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Answer:
<em>The programming language is not stated; however, I'll answer using Python programming language (</em><em>Se</em><em>e attachment</em><em> </em><em>for</em><em> </em><em>proper </em><em>for</em><em>mat</em><em>)</em>
tuition = 10000
rate = 0.04
for i in range(1,15):
tuition = tuition + tuition * rate
if i <= 10:
print("Year "+str(i)+" tuition:",end=" ")
print(round(tuition,2))
if i == 14:
print("Tuition 4th year after:",end=" ")
print(round(tuition,2))
Explanation:
<em>The first 2 lines initializes tuition and rate to 10000 and 0.04 respectively</em>
tuition = 10000
rate = 0.04
<em>The next line iterates from year 1 to year 14</em>
for i in range(1,15):
<em>This line calculates the tuition for each year</em>
tuition = tuition + tuition * rate
<em>The next 3 lines prints the tuition for year 1 to year 10</em>
if i <= 10:
print("Year "+str(i)+" tuition:",end=" ")
print(round(tuition,2))
<em>The next 3 lines prints the tuition at the 4th year after year 10 (i.e. year 14)</em>
if i == 14:
print("Tuition 4th year after:",end=" ")
print(round(tuition,2))
Answer:
The given problem is solved using language - Python.
def f(x):
new_list=[]
for i in x:
if i%2==0:
new_list.append(i//2)
else:
new_list.append(i*2)
return new_list
my_list=list(range(1,6))
print('Original List:',my_list)
my_list=f(my_list)
print('Modified List:',my_list)
- Create a new list.
- Iterate over the list passed into the function.
- Check if the element is even or not. If true, append half the value of element in the list.
- If false, append twice the value of the element in the list.
- At last, return the new list.
There is another way of doing this - By using map() function.
—————————————————————————————
def f(x):
return list(map(lambda x:x//2 if x%2==0 else 2*x,x))
my_list=list(range(1,6))
print('Original List:',my_list)
my_list=f(2my_list)
print('Modified List:',my_list)
—————————————————————————————
Original List: [1, 2, 3, 4, 5]
Modified List: [2, 1, 6, 2, 10]