Answer:
3
Step-by-step explanation:
Answer:
t=3.5 seconds
Step-by-step explanation:
Given
h(t) = −16t^2 + 111t + 0
h'(t)= -32t + 111
Maximum height occurs when h(t) = 0 and the ball begins to fall
h(t)= -32t + 111=0
-32t + 111=0
-32t=-111
Divide both sides by -32
t=3.46872
Approximately, t=3.5 seconds
Recall,
Maximum height occurs when h(t) = 0
h(t)= -32t + 111=0
= -32(3.46872)+111
= -110.99904+111
= 0.00096 ft
One number is 18 and the other is 22
For y=3x+4, you would put 4 on the y-intercept and from that point you go up 3 and right 1 and then plot the second point.
For y=-x-4, you would put -4 on the y-intercept and from that point go down 1 and right 1 and then plot the second point.
Y = x - 1
y = -5 - 1
y = -6
(x, y) = (-5, -6)
y = x - 1
y = -3 - 1
y = -4
(x, y) = (-3, -4)
y = x - 1
y = 0 - 1
y = -1
(x, y) = (0, -1)
y = x - 1
y = 1 - 1
y = 0
(x, y) = (1, 0)
y = x - 1
y = 2 - 1
y = 1
(x, y) = (2, 1)
