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nikitadnepr [17]
3 years ago
5

If a-b=10 and a+b=31 what is the value of 3a-2b

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
7 0

a - b = 10

a + b = 31

(a - b) + (a + b) = 10 + 31

2a = 41

a = 41/2

41/2 - b = 10

b = 21/2

3a - 2b = 3(41/2) - 2(21/2) = 81/2

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IF THE ODDS AGAINST A PARTICULAR CANDIDATE WINNING AN ELECTION ARE 9
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The probability that the candidate will win is P = 0.357

<h3>How to find the probability?</h3>

We know that the odds against the particular candidate are 9 to 5.

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Answer:

Assuming population data

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Assuming sample data

s = \sqrt{0.000425}=0.0206

Step-by-step explanation:

For this case we have the following data given:

736.352, 736.363, 736.375, 736.324, 736.358, and 736.383.

The first step in order to calculate the standard deviation is calculate the mean.

Assuming population data

\mu = \frac{\sum_{i=1}^6 X_i}{6}

The value for the mean would be:

\mu = \frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359

And the population variance would be given by:

\sigma^2 = \frac{\sum_{i=1}^6 (x_i-\bar x)}{6}

And we got \sigma^2 =0.000354

And the deviation would be just the square root of the variance:

\sigma = \sqrt{0.000354}=0.0188

Assuming sample data

\bar X = \frac{\sum_{i=1}^6 X_i}{6}

The value for the mean would be:

\bar X = \frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359

And the population variance would be given by:

s^2 = \frac{\sum_{i=1}^6 (x_i-\bar x)}{6-1}

And we got s^2 =0.000425

And the deviation would be just the square root of the variance:

s = \sqrt{0.000425}=0.0206

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