Sub x = 2-y^2 to Q, we get:
Q = 3(2-y^2)*y^2
let y^2 = k
Q = 3(2-k)k = 3(2k-k^2)
2k-k^2 has a max when k = 1
Then y^2 = 1 -> y = 1 or -1
I’m gonna say no since it’s 5.74 and it isn’t repeating
Answer:
Step-by-step explanation:
178.54-35.65=142.89
then you do 142.89/12.99=11
She bought 11 CDs
Answer:
Negative
Step-by-step explanation:
- –54 ÷ 6 = -9
The perimeter of the triangle is 40 units
<h3>Perimeter of a triangle</h3>
From the question, we are to determine the perimeter of the given triangle
From the given diagram, we can observe that the triangle is a right triangle
The vertical length of the triangle is 15 units
and the horizontal length of the triangle is 8 units
Thus,
We can find the hypotenuse by using the<em> Pythagorean theorem </em>
Let the hypotenuse be h
Then,
h² = 15² + 8²
h² = 225 + 64
h² = 289
h = √289
h = 17 units
Now, for the perimeter of the triangle
The perimeter of a triangle is the sum of all its three sides
Thus,
The perimeter. P, of the triangle is
P = 15 + 8 + 17
P = 40 units
Hence, the perimeter of the triangle is 40 units
Learn more on Calculating perimeter here: brainly.com/question/17394545
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