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lesantik [10]
3 years ago
6

PLEASE HELP WITH MATH AND BEST GETS BRAINLIEST. PLEASE SHOW WORK.

Mathematics
2 answers:
faltersainse [42]3 years ago
6 0
So you have to fine the total volume of the pool which is 1274 feet. then multiply that by 7.48 to get 9529.52. so thats how much water is held in the pool at 100%. so now you can divide 9529.52 by 10 to get you 10% of the pool which is 952.952. then multiply that by 8 to get 7623.616 gallons of water. and thats your answer.
rosijanka [135]3 years ago
6 0
The volume of the water in the pool is (24.5 x 13 x 4) cubic feet.

The number of gallons is (24.5 x 13 x 4 cubic feet) x (7.48 gal/cu-ft)

80% means 0.80 .

To fill the pool to 80% of capacity, it takes

         (0.8) x (24.5 x 13 x 4 cubic feet) x (7.48 gal/cu-ft) gallons.
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What is the solution to the equation 1/4x +2= -5/8x - 5
nalin [4]

Answer:

x = -8

Step-by-step explanation:

1/4x +2= -5/8x - 5

Add 5/8x to each side

1/4x +5/8x +2= -5/8x+5/8x - 5

1/4x+5/8x +2=  - 5

Subtract 2 from each side

1/4x+5/8x +2-2=  - 5-2

1/4x+5/8x =  - 7

Get a common denominator

1/4 *2/2 x + 5/8x = -7

2/8x + 5/8x = -7

7/8x = -7

Multiply each side by 8/7

8/7x * 7/8x = -7 *8/7

x = -8

7 0
3 years ago
Read 2 more answers
The Board of Directors of a small company consists of five people. Two of those directors are considered "strong leaders". If th
Pavel [41]
1: 40%
2: 30%
3: 20%

If we know one of the succeeded, then 
1: 44.44%
2: 33.33%
3: 22.22%

If under the circumstance that they all fail to meet a strong leader, the board picks one of them at random,
1: 43.33%
2: 33.33%
3: 23.33%

The first person has a 2 in 5 chance of randomly getting a strong leader. If the first person doesn't find a strong leader, the second person has a 2/4 chance of getting a strong leader. If neither the first nor second person gets a strong leader, the third sales person has a 2/3 chance of getting a strong leader.

1: 2/5=40% Chance
2: (3/5)*(2/4)=30% Chance You have to take the probability the first rep failed to get a strong leader, then multiply by the probability the second rep gets a strong leader.
3: (3/5)*(2/4)*(2/3)=20% You have to take the probability both the other people failed, then multiply by the probability they succeeded.
7 0
4 years ago
Find the labeled angles​
ipn [44]

Answer:

X = 25, Angles are 65 degrees

Step-by-step explanation:

3x-10 = x+40

2x=50

x=25

8 0
4 years ago
If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by
Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by y = 70t-16t^2.

To find : The average velocity for the time period beginning when t = 2 and lasting.  a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :    

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}

(\text{Average velocity})_{0.1\ s}=696\ ft/s

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}

(\text{Average velocity})_{0.01\ s}=7536\ ft/s

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}  

(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}

(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}

(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}

(\text{Average velocity})_{0.001\ s}=75936\ ft/s

5 0
4 years ago
At a concession stand one person purchased 3 drinks and 3 soft pretzels for a total of $9.00 another person purchased 4 drinks a
kherson [118]

<span>d=drinks
p=pretzels
1st eq. 3d+3p=9.00
2nd eq. 4d+2p=8.50</span>

multiply 1st eq by 2

6d+6p=18.00

<span>multiply 2nd eq by 3
12d+6p=25.50
subtract
-6d=-7.50
d=1.25
3p=9.00-3d</span>

3p=9-3.75

<span>3p=5.25
p=1.75
price of a pretzel=$1.75</span>

<span> price of a drink = $1.25</span>


7 0
3 years ago
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