HELP WITH THE QUESTIONS

Which point lies on the graph of the function shown below?<br><br> y= -x^2 + 4x -2

Nata [24]

I'm pretty sure quadrant II (2,2)

7 0

3 years ago

Solve for y you will get brainliest

77julia77 [94]

y = 3p+85, because they are vertical angles.

x = 2p ‐ 10, because they are vertical angles too.

4 0

3 years ago

PLZ HELP (40 POINTS)<br> 3 QUESTIONS

8090 [49]

Answer:

first one is D

second is B

third is B

Step-by-step explanation:

5 0

3 years ago

How do you solve these equations? I don't want you to answer all of them, just tell me how to solve each type of equation on the

miss Akunina [59]

Answer:

8. Identify the common denominator; express each fraction using that denominator; combine the numerators of those rewritten fractions and express the result over the common denominator. Factor out any common factors from numerator and denominator in your result. (It's exactly the same set of instructions that apply for completely numerical fractions.)

9. As with numerical fractions, multiply the numerator by the inverse of the denominator; cancel common factors from numerator and denominator.

10. The method often recommended is to multiply the equation by a common denominator to eliminate the fractions. Then solve in the usual way. Check all answers. If one of the answers makes your multiplier (common denominator) be zero, it is extraneous. (10a cannot have extraneous solutions; 10b might)

Step-by-step explanation:

For a couple of these, it is helpful to remember that (a-b) = -(b-a).

$\dfrac{5}{x+2}+\dfrac{25-x}{x^2-3x-10}=\dfrac{5(x-5)}{(x+2)(x-5)}+\dfrac{25-x}{(x+2)(x-5)}\\\\=\dfrac{5x-25+25-x}{(x+2)(x-5)}=\dfrac{4x}{x^2-3x-10}$

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$\displaystyle\frac{\left(\frac{x}{x-2}\right)}{\left(\frac{2x}{2-x}\right)}=\frac{x}{x-2}\cdot\frac{-(x-2)}{2x}=\frac{-x(x-2)}{2x(x-2)}=-\frac{1}{2}$

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$\dfrac{3}{x-1}+\dfrac{6}{x^2-3x+2}=2\\\\\dfrac{3(x-2)}{(x-1)(x-2)}+\dfrac{6}{(x-1)(x-2)}=\dfrac{2(x-1)(x-2)}{(x-1)(x-2)}\\\\3x-6+6=2(x^2-3x+2) \qquad\text{multiply by the denominator}\\\\2x^2-9x+4=0 \qquad\text{subtract 3x}\\\\(2x-1)(x-4)=0 \qquad\text{factor; x=1/2, x=4}$

Neither solution makes any denominator be zero, so both are good solutions.

8 0

3 years ago

In a soccer game the winner gains 3 points, while the loser gains 0 points. If the game is a draw, then the two teams gain 1 poi

Mariana [72]

Answer:

10 losses

Step-by-step explanation:

Here, we want to get the greatest possible number of games the team lost

Let the number of games won be x

Number drawn be y

Number lost be z

Mathematically;

x + y + z = 38

Let’s now work with the points

3(x) + 1(y) + z(0) = 80

3x + y = 80

So we have two equations here;

x + y + z = 80

3x + y = 80

The greatest possible number of games lost will minimize both the number of games won and the number of games drawn

We can have the following possible combinations of draws and wins;

26-2

25-5

24-8

23-11

22-14

21-17

21-17 is the highest possible to give a loss of zero

Subtracting each sum from 38, we have the following loses:

10, 8, 6, 4, 2 and 0

This shows the greatest possible number of games lost is 10

5 0

2 years ago