Answer:
E. 1/16
Explanation:
In a duplicate dominant epistasis, when one locus presents a dominant genotype and the other presents a recessive genotype, the dominant one hides the effective of the recessive gene. Therefore, a recessive phenotype will only be observed when both genes are recessive homozygous (aabb).
Assuming a doubly-heterozygous mating (AaBb x AaBb), the probability that both genes are recessive homozygous is:
![P=\frac{1}{2}*\frac{1}{2}*\frac{1}{2}*\frac{1}{2}\\P =\frac{1}{16}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B1%7D%7B2%7D%2A%5Cfrac%7B1%7D%7B2%7D%2A%5Cfrac%7B1%7D%7B2%7D%2A%5Cfrac%7B1%7D%7B2%7D%5C%5CP%20%3D%5Cfrac%7B1%7D%7B16%7D)
1/16 of offspring are expected to show the recessive phenotype.
Answer:
The lag phase
Explanation:
The lag phase is the initial phase of bacterial growth curve where new bacterial cells are still adapting to their new environment and preparing themselves for the digestion of new medium (nutrient supply). They are metabolizing but not yet growing at this phase.
After the lag phase follows the log phase where bacteria starts to grow in logarithmic manner, releasing energy and waste as they start utilizing provided nutrients.
<span>A.let myself feel sad and then find ways to move on</span>
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