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Alex
3 years ago
8

Large layers of cross-bedded sand can be indicative of a __________ environment.

Biology
1 answer:
k0ka [10]3 years ago
6 0
Layers of cross-bedded sand can be indicative of a DESERT environment wind is responsible for the formation of these sedimentary structures. Sand dunes preserved in rocks can be quite large. These structures form as a result of the migration of dunes due to the action of the wind. Dunes are not often preserved but a few can be observed in thick sandstone units. 
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Secretors (genotypes ss and ss) secrete their a and b blood group antigens into their saliva and other body fluids, while nonsec
Solnce55 [7]
As you can see from the image presented below when parents with AB Ss and AA ss genotypes cross we get three distinct phenotype groups.
Marked in red are the individuals whose A type blood we can determine from the saliva because they have at least one S allele.
Marked in light green are the individuals whose AB type of blood we can determine from the saliva too.
And marked in orange are the individuals that are homozygous recessive for the s allele, and we could not determine their blood type from their saliva.

5 0
3 years ago
DUE IN 12 MIN Please help me with these, will mark brainliest
USPshnik [31]

Answer:

I am certain the answer is A sorry if im wrong

Explanation:

5 0
3 years ago
Enter your answer in the provided box. what is the value of ni for an electron that emits a photon of wavelength 95.04 nm when i
Sloan [31]
<span>Ni = 5 The Rydberg formula for hydrogen is 1/w = R(1/a^2 - 1/b^2) where w = wavelength in vacuum R = Rydberg constant 1.0973731568508x10^7 1/m a,b = integers greater than or equal to 1 and a < b Now we need to select the value for a. a = 1 will converge towards 91.13 nm a = 2 converges towards 364.51 nm a = 3 converges towards 820.14 nm ... Because of this, we will assume a = 1 for this problem since it converges closest to the wavelength given. Substitute known values 1/w = R(1/a^2 - 1/b^2) 1/9.504x10^-8 = 1.0973731568508x10^7(1/1^2 - 1/b^2) 10521885.52 = 1.0973731568508x10^7(1/1 - 1/b^2) 0.958824759 = 1 - 1/b^2 -0.041175241 = -1/b^2 0.041175241 = 1/b^2 24.28643927 = b^2 4.928127359 = b So Ni = 5.</span>
3 0
3 years ago
1.
MAVERICK [17]

Answer:

1. Purines

2. States that DNA composition varies among species

3. Hydrogen Bond

4. Purines

<em>Answer to #2 is a little iffy </em>-- sorry

Explanation:

Pyrmidines have two rings

Purines have one ring

Complementary bases are connected by hydrogen bonds.

4 0
3 years ago
In observing epithelial cells under a microscope, the cells are arranged in a single layer and look tall and narrow, and the nuc
Kipish [7]

Answer:

Columnar epithelial tissue.

Explanation:

The above scenario confirms that these are simple columnar epithelial tissue because columnar cells are tall, narrow and nucleus in the tall column like cells located at the basal end of the cells. Columnar epithelial tissue are responsible for absorption and secretion of molecules. These are present at some part of digestive tract, female reproductive tract, and respiratory system.

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3 years ago
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