
2) 5.625 mg will be left
Explanation:
1) Half-life = 17.5 days
initial amount of Arsenic-74 = 90 mg
To get the equation, we will use the equation of half-life:


2) we need to find the remaining amount of Arsenic-74 after 70 days
t = 70

So after 70 days, 5.625 mg will be left
8, 15, 17
You can do this by using the Pythagorean Theorem and setting the sides equal to
shorter leg = x
longer leg = x + 7
hypotenuse = 2x + 1
Then solve so that one side is equal to zero and use the quadratic formula.
You can figure out how many miles per hour it travels by dividing 18/3. This gives us the answer of 6. 3/4 = 0.75 so we can multiply 6 * 0.75 to get 4.5 as our final answer. It will travel 4.5 miles in 3/4 of an hour.
Answers:
10) y= 1/2x - 2
11) y= 2x + 3
12) y= 2/3x - 4
I found this by using y=mx+ b
Answer:
1 and 1/8 of a batch
Step-by-step explanation:
First you multiply 1/2 by 4 and get for 8 and then you subtract 4/8 - 3/8 and you take the sum of that and add one hole