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Mashutka [201]
3 years ago
7

The set of odd numbers greater than 19 ? Infinite or finite

Mathematics
1 answer:
allochka39001 [22]3 years ago
7 0

Answer: Infinite

Odd numbers are of the form 2n+1, where n is an integer

Solving 2n+1 > 19 leads to n > 9. There are infinitely many integers that make the inequality n > 9 to be true.

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Answer: -105x^5 + 67x^4 + 240x^3 -100x^2

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The question says~<br><br>Find the number that makes the ratio equivalent to 1:4....<br><br>4: ?​
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Step-by-step explanation:

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One of the legs of a right triangle measures 9 cm and the other leg measures 11 cm.
ikadub [295]

Answer:

\boxed {\boxed {\sf 14.2 \ cm}}

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean Theorem to solve for the sides.

a^2+b^2=c^2

where <em>a</em> and<em> b</em> are the legs and <em>c</em> is the hypotenuse. In this triangle, we know the legs are 9 centimeters and 11 centimeters, or:

  • a= 9 cm
  • b= 11 cm

Substitute these values into the formula.

(9 \ cm)^{2}  +(11 \ cm)^{2} =c^{2}

Solve the exponents.

  • (9 cm)²= 9 cm*9 cm=81 cm²

81 \ cm^{2}  +(11 \ cm)^{2} =c^{2}

  • (11 cm)²= 11 cm*11 cm= 121 cm²

81 \ cm^{2}  +121 cm^{2} =c^{2}

Add the values on the left side.

202 \ cm^{2} =c^{2}

Since we are solving for c, we must isolate the variable. It is being squared and the inverse of a square is the square root. Take the square root of both sides.

\sqrt {202 \ cm^{2} }=\sqrt{c^{2} }

\sqrt {202 \ cm^{2} }=c

14.2126704036 \ cm =c

We are told to round to the nearest tenth.

  • 14.2<u>1</u>26704036

The 1 in the hundredth place tells us to leave the 2 in the tenth place.

14.2 \ cm= c

The hypotenuse is equal to <u>14.2 centimeters.</u>

3 0
3 years ago
10. Marcelle uses a total of 6 plates to add 110
madam [21]

Answer:

Marcelle will use 4 plates of the 25 lb & 2 plates of the 5 lb to fabricate the 110 lb weight lifting bar.

Step-by-step explanation:

There are 6 plates which consist of 25 lb plates and 5 lb plates.

We need to figure out how many of each one compose 110 lb.

Thus, 25 x 4 = 100... 4 plates of 25 pounds.

5 x 2 = 10 ... 2 plates of 5 lbs.

100+10= 110, which is our goal! And a total of 6 plates were used!

All things put into great consideration, Marcelle will use 4 plates of the 25 lb & 2 plates of the 5 lb to fabricate the 110 lb weight lifting bar.

I hope this helped!

~ Penny

5 0
3 years ago
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