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Gre4nikov [31]
4 years ago
5

If f (x) =6x-9, find f(4)​

Mathematics
2 answers:
Elden [556K]4 years ago
8 0

Answer:

f (x) =6x-9

f (4) =(6×4) -9

f (4) =24-9

f (4) = 15

kap26 [50]4 years ago
5 0

Answer:

f(4)= 15

Step-by-step explanation:

f (x) =6x-9

      = 6(4)-9

      =24-9

f(4) = 15

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A vet weighs two puppies. The small puppy weighs 4 2/3 pounds. The large puppy weighs 4 2/3 times as much as the small puppy. Ho
Maksim231197 [3]
4 2/3 lbs = small puppy weight
4 2/3 times the small puppies weight = large puppy weight
          4 2/3 × 4 2/3  or 4 2/3^2  = 21.77777.... or in mixed number is 21 7/9 lbs
4 0
4 years ago
2/3 x - 1/5x = x - 1
Novay_Z [31]

Answer:

10/15x-3/15x=x-1

7/15x=x-1

x=7/15x+1

8/15x=1

x=15/8

5 0
3 years ago
-3=n/2-6 help pleaseeee!!!!
frozen [14]

Answer:

6 = n

Step-by-step explanation:

-3=n/2-6

Add 6 to each side

-3+6 = n/2 -6+6

3 = n/2

Multiply each side by 2

3*2 = n/2 *2

6 = n

5 0
4 years ago
Read 2 more answers
Yet another question.
inna [77]

Answer:

t= 3 years

Step-by-step explanation:

So far we have 2 useful relationshipsP_{t}= P_{o} e^{r*t} and P_{t}=2P_{0}

Now, clearing t

P_{t}= P_{o} e^{r*t} \\\frac{ P_{t}}{P_{o}} = e^{r*t}\\\frac{2 P_{0}}{P_{o}} = e^{r*t}\\2 = e^{r*t}

I apply logarithm

log(2)=r*t\\ t=\frac{log(2)}{r}\\t=\frac{0.3}{0.1} \\ t=3 years

Done

4 0
4 years ago
An elephant can run 4 of a mile in 36 seconds. At this rate, which expression can be
statuscvo [17]

Answer:

One-fourth mile over thirty-six seconds = 25 miles per hour.

Step-by-step explanation:

We have been given that an elephant can run one over four of a mile in 36 seconds.

To find elephant's rate in miles per hour, we will convert our given time in hours as shown below:

0.25mile/36sec * 60sec/1min * 60min/1hr

900miles/36hr

25miles/hr

Therefore, It's One-fourth mile over thirty-six seconds = 25 miles per hour.

7 0
3 years ago
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