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Ksenya-84 [330]
3 years ago
15

A rectangle has a length of x and a width of 5x^3+4-x^2. What is the polynomial that models the perimeter of the rectangle

Mathematics
1 answer:
sveticcg [70]3 years ago
8 0

Answer:

L= x

And the width for this case is:

W= 5x^3 +4 -x^2

And we know that the perimeter is given by:

P= 2L +2W

And replacing we got:

P(x) = 2x +2(5x^3 +4 -x^2)= 2x +10x^3 +8 -2x^2

And symplifying we got:

P(x)= 10x^3 -2x^2 +2x+8

Step-by-step explanation:

For this problem we know that the lenght of the rectangle is given by:

L= x

And the width for this case is:

W= 5x^3 +4 -x^2

And we know that the perimeter is given by:

P= 2L +2W

And replacing we got:

P(x) = 2x +2(5x^3 +4 -x^2)= 2x +10x^3 +8 -2x^2

And symplifying we got:

P(x)= 10x^3 -2x^2 +2x+8

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Riley has decided to become an engineer. Outline the steps she should take in researching her education options.
Rus_ich [418]

Answer:    

  • Earn a bachelor’s degree from an ABET-accredited universityEstablish licensure through the NCEES FE exam
  • Earn a master’s degree in a sub-discipline of engineering
  • Gain practical experience in the field
  • Earn a professional engineering (PE) license in a sub-discipline of engineering
  • Attain further professional certification or join professional societies

Step-by-step explanation: Hope this helped :)

5 0
3 years ago
Engineers must consider the diameters of heads when designing helmets. The company researchers have determined that the populati
Margaret [11]

Answer:

1. The minimum head breadth that will fit the clientele is of 4.41-in.

2. The maximum head breadth that will fit the clientele is of 7.19-in.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean of 5.8-in and a standard deviation of 0.8-in.

This means that \mu = 5.8, \sigma = 0.8

1. What is the minimum head breadth that will fit the clientele?

The 4.1st percentile, that is, X when Z has a pvalue of 0.041, so X when Z = -1.74.

Z = \frac{X - \mu}{\sigma}

-1.74 = \frac{X - 5.8}{0.8}

X - 5.8 = -1.74*0.8

X = 4.41

The minimum head breadth that will fit the clientele is of 4.41-in.

2. What is the maximum head breadth that will fit the clientele?

100 - 4.1 = 95.9th percentile, that is, X when Z has a pvalue of 0.959, so X when Z = 1.74.

Z = \frac{X - \mu}{\sigma}

1.74 = \frac{X - 5.8}{0.8}

X - 5.8 = 1.74*0.8

X = 7.19

The maximum head breadth that will fit the clientele is of 7.19-in.

8 0
3 years ago
The auto parts department of an automotive dealership sends out a mean of 4.2 special orders daily. What is the probability that
gregori [183]

The probability that, for any day, the number of special orders sent out will be exactly 3 is 0.1633.

<h3>What are some of the properties of Poisson distribution?</h3>

The Poisson distribution is a discrete probability distribution that describes the likelihood of a specific number of events occurring in a specified span of time or space, if these events occur at a constant mean rate and regardless of the time since the last occurrence.

Let X ~ Pois(λ)

Then we have:

E(X) = λ = Var(X)

Since standard deviation is the square root (positive) of variance,

Thus,

The standard deviation of X = \sqrt{\lambda}

Its probability function is given by

f(k; λ) = Pr(X = k) =   \dfrac{\lambda^{k}e^{-\lambda}}{k!}

Given the mean is 4.2.

We have to find the probability that on any day, the number of special orders sent out will be exactly 3. Therefore, the value of x will be 5.

Using the Poisson distribution,

P(x) = \dfrac{e^{-\lambda}\lambda ^x}{x!}\\\\P(5) =\dfrac{e^{-4.2}(4.2)^5}{5!}\\\\P(5) = 0.1633

Hence, the probability that, for any day, the number of special orders sent out will be exactly 3 is 0.1633.

Learn more about Poisson distribution here:

brainly.com/question/7879375

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5 0
2 years ago
What is the quotient of the following division problem? 328 ÷ 172 = ?
mojhsa [17]

Answer:

C

Step-by-step explanation:

328÷172 how many times can 328 go into 172 so u have to multiply 172 by 2 if it goes over then put on top of the one and then subtract 328 by 172 and u got ur answer and remaining

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3 years ago
You bought a magazine for $ 5 and four candy bars . You spent a total of $ 11 . How much did each candy bar cost ?
inn [45]

Answer:

$1,5

Step-by-step explanation:

total money spent - cost of magazine = money spent on candy bars

$11 - $5 = $6

money spent on candy bars divided by number of candy bars = price of one candy bar

$6 / 4 = $1,5

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2 years ago
Read 2 more answers
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