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Shtirlitz [24]
3 years ago
6

Tanx-cotx=0 solve in radians

Mathematics
1 answer:
Alex Ar [27]3 years ago
6 0
 <span>tan x + 1 / tan x = 2 

tan^2 x + 1 = 2 tan x 

tan^2 x - 2 tan x + 1 = 0 

( tan x - 1 )^2 = 0 

tan x = 1 

x = π/4 , 5π/4

</span>
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Answer:

The sides of the first quadrilateral are 60 in, 40 in, 30 in and 12,5 in

The sides of the second quadrilateral are 24 in, 16 in, 12 in and 5 in

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional, and this ratio is called the scale factor

Arrange the sides of each quadrilateral from largest to smallest

<u><em>First quadrilateral </em></u>            <u><em>Second quadrilateral</em></u>

Longest side=60 in          Longest side=c in

Second side=40 in           Second side=16 in

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so

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<em>Find the value of c</em>

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c=60(16)/40

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<em>Find the value of a</em>

\frac{40}{16}=\frac{a}{12}

a=40(12)/16

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<em>Find the value of b</em>

\frac{40}{16}=\frac{b}{5}

b=40(5)/16

b=12.5\ in

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