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Shtirlitz [24]
3 years ago
6

Tanx-cotx=0 solve in radians

Mathematics
1 answer:
Alex Ar [27]3 years ago
6 0
 <span>tan x + 1 / tan x = 2 

tan^2 x + 1 = 2 tan x 

tan^2 x - 2 tan x + 1 = 0 

( tan x - 1 )^2 = 0 

tan x = 1 

x = π/4 , 5π/4

</span>
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Solve xy-6=k for x <br><br><br> Please help me out
dedylja [7]

Answer:

\times  =  \frac{k + 6}{y}

Step-by-step explanation:

xy - 6 = k \\ xy = k + 6 \\ x =  \frac{k + 6}{y}

4 0
3 years ago
Complete the square and write in standard form. Show all work.What would be the conic section:CircleEllipseHyperbolaParabola
mote1985 [20]

ANSWER

This is an ellipse. The equation is:

\frac{(x-1)^2}{3^2}+\frac{(y+4)^2}{4^2}=1

EXPLANATION

We have to complete the square for each variable. To do so, we have to take the first two terms and compare them with the perfect binomial squared formula,

(a+b)^2=a^2+2ab+b^2

For x we have to take 16x² and -32x. Since the coefficient of x is not 1, first, we have to factor out the coefficient 16,

16x^2-32x=16(x^2-2x)

Now, the first term of the expanded binomial would be x and the second term -2x. Thus, the binomial is,

(x-1)^2=x^2-2x+1

To maintain the equation, we have to subtract 1,

16(x^2-2x+1-1)=16((x-1)^2-1)=16(x-1)^2-16

Now, we replace (16x² - 32x) from the given equation by this equivalent expression,

16(x-1)^2-16+9y^2+72y+16=0

The next step is to do the same for y. We have the terms 9y² + 72y. Again, since the coefficient of y² is not 1, we factor out the coefficient 9,

9y^2+72y=9(y^2+8y)

Following the same reasoning as before, we have that the perfect binomial squared is,

(y+4)^2=y^2+8y+16

Remember to subtract the independent term to maintain the equation,

9(y^2+8y)=9(y^2+8y+16-16)=9((y+4)^2-16)=9(y+4)^2-144

And now, as we did for x, replace the two terms (9y² + 72y) with this equivalent expression in the equation,

16(x-1)^2-16+9(y+4)^2-144+16=0

Add like terms,

\begin{gathered} 16(x-1)^2+9(y+4)^2+(-16-144+16)=0 \\ 16(x-1)^2+9(y+4)^2-144=0 \end{gathered}

Add 144 to both sides,

\begin{gathered} 16(x-1)^2+9(y+4)^2-144+144=0+144 \\ 16(x-1)^2+9(y+4)^2=144 \end{gathered}

As we can see, this is the equation of an ellipse. Its standard form is,

\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1

So the next step is to divide both sides by 144 and also write the coefficients as fractions in the denominator,

\begin{gathered} \frac{16(x-1)^2}{144}+\frac{9(y+4)^2}{144}=\frac{144}{144} \\  \\ \frac{(x-1)^2}{\frac{144}{16}}+\frac{(y+4)^2}{\frac{144}{9}}=1 \end{gathered}

Finally, we have to write the denominators as perfect squares, so we identify the values of a and b. 144 is 12², 16 is 4² and 9 is 3²,

\frac{(x-1)^2}{(\frac{12}{4})^2}+\frac{(y+4)^2}{(\frac{12}{3})^2}=1

Note that we can simplify a and b,

\frac{12}{4}=3\text{ and }\frac{12}{3}=4

Hence, the equation of the ellipse is,

\frac{(x-1)^2}{3^2}+\frac{(y+4)^2}{4^2}=1

3 0
1 year ago
The price of a pizza plus 12% delivery charge comes to a total cost of $17.92. What was the price of the pizza?
Leya [2.2K]

Answer:

i believe the answer is 14.93 dollars.

Step-by-step explanation:

3 0
2 years ago
Please help! Correct answer only, please! Consider the following information matrices for the price of clothing at a clothing st
ololo11 [35]

Answer: b) Large blue t-shirt & Medium RC jeans

<u>Step-by-step explanation:</u>

The subscript numbers attached to the matrix letter represents the:

ROW, COLUMN

A=\left[\begin{array}{ccc}a_{1,1}&a_{1, 2}&a_{1, 3}\\a_{2,1}&a_{2, 2}&a_{2, 3}\\a_{3,1}&a_{3, 2}&a_{3, 3}\end{array}\right] \qquad B=\left[\begin{array}{ccc}a_{1,1}&b_{1, 2}&b_{1, 3}\\b_{2,1}&b_{2, 2}&b_{2, 3}\\b_{3,1}&b_{3, 2}&b_{3, 3}\end{array}\right]\\

A₁,₃ = 1st row, 3rd column

         1st row is Blue, 3rd column is Large

B₃,₂ = 3rd row, 2nd column

         3rd row is RC jeans, 2nd column is Medium

A₁,₃ + B₃,₂ = Large blue t-shirt & Medium RC jeans

8 0
3 years ago
How do you write this number using words?<br><br> 47
jasenka [17]
Answer is fourty seven 
4 0
3 years ago
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