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Butoxors [25]
3 years ago
5

WILL MARK BRAINLIEST!!! HELP ASAP!!!!

Mathematics
2 answers:
Elza [17]3 years ago
7 0

Answer:

3 2/3.

Step-by-step explanation:

1 5/6 * 2

= 11/6 * 2

= 22/6

= 11/3

= 3 2/3

mafiozo [28]3 years ago
6 0
1 5/6 × 2= 2.66 or 2 2/3.

HOPE THIS HELPS!!!!

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Which inequality represents all values of x for which the quotient below is<br> defined?
garri49 [273]

Answer:

Option B: x > 0

Step-by-step explanation:

Option A is wrong because \sqrt{3(0)}will be 0. So, the inequality can't be divided by 0.

Option C is wrong because 1 will suffice this inequality. \sqrt{7}/\sqrt{3}=1.5 (approx)

Option D is wrong because any value in the root has to be greater or equal to 0 (otherwise, it's imaginary number). -1 will give the latter root a value of root-(-3).

Leaving us with only option B, which is the right answer.

7 0
3 years ago
Which equation is NOT true?
Arlecino [84]

Answer:

{ \bf{15x + 30 = 180}}

3 0
3 years ago
12345678910 0.9 written as a fraction is _____. 1
ICE Princess25 [194]

Answer: 9/10


Step-by-step explanation:


6 0
3 years ago
Credit sales are collected as follows:65 percent in the month of the sale.25 percent in the month after the sale.10 percent in t
Vitek1552 [10]

Answer:

Step-by-step explanation:

a) November sales = (Total Uncollected Sales - Uncollected Sales from December) / Collection rate after two months

= ($121,100 - $87,300) / 0.20

November sales = $169, 000.00

b) December sales = Uncollected sales from December / Collection rate of the previous month sales,

Therefore: December sales = $87,300 / 0.45 = $194,000

December sales = $194,000.00

c) Each month's collection for the company are:

Collections for ech month = 0.20(Sales from 2 months ago) + 0.25(Last month's sales) + 0.55 (Current sales)

January collections = 0.20($169000.00) + 0.25($194,000.00) + 0.55($132,000)

January collections = $154,900.00

February collections = 0.20($194,000.00) + 0.25($132,000) + 0.55($149,000)

February collections = $153,750.00

March collections = 0.20($132,000) + 0.25($149,000) + 0.55($164,000)

March collections = $153,850.00

4 0
4 years ago
The quantities xxx and yyy are proportional. xxx yyy 111111 1\dfrac{2}{9}1 9 2 ​ 1, start fraction, 2, divided by, 9, end fracti
jolli1 [7]

Question:

The quantities x and y are proportional.

x\ \ \ \ \ \ \ \ \ \ y \\1\frac{2}{9}\ \ \ \ \ \ \ 2\frac{1}{3}

Find the constant of proportionality (r)

Answer:

r = 1\frac{10}{11}

Step-by-step explanation:

Given

x\ \ \ \ \ \ \ \ \ \ y \\1\frac{2}{9}\ \ \ \ \ \ \ 2\frac{1}{3}

Required

Determine the constant of proportionality (r)

Constant of proportionality (r) is calculated as

y = rx

When

y = 2\frac{1}{3}       x = 1\frac{2}{9}

Substitute these values in the given formula

2\frac{1}{3} = r * 1\frac{2}{9}

Convert both fractions to improper fractions

\frac{7}{3} = r * \frac{11}{9}

Multiply both sides by \frac{9}{11}

\frac{7}{3} * \frac{9}{11}= r * \frac{11}{9} * \frac{9}{11}

\frac{7}{3} * \frac{9}{11}= r

Reorder

r = \frac{7}{3} * \frac{9}{11}

r = \frac{7 * 9}{3 * 11}

Divide the numerator and denominator by 3

r = \frac{7 * 3}{11}

r = \frac{21}{11}

Convert to mixed fraction

r = 1\frac{10}{11}

<em>Hence, the constant of proportionality is </em>1\frac{10}{11}<em></em>

4 0
3 years ago
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