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3 years ago

Help!!!i never learned this

Mathematics

1 answer:

andre [41]3 years ago

5 0

I hope this helps you

perpendicular lines slopes multiplication -1

M1×M2= -1

1/2×M2= -1

M2= -2

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3,668>13,667 yes or no

adelina 88 [10]

Answer:

No it is not right

3,668 < 13,667

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2 years ago

Enter the equation of the line in the form y=mx where m is the slope.Immersive Reader

kari74 [83]

Answer:

y = 1/2x

Step-by-step explanation:

The slope is the rise (up) over run (left or right depending on if the number is negative) between points. So the next point on the graph is up 5 and over 10. this simplified is 1/2. Then you put this into y=mx which is y=1/2x

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3 years ago

Determine what shape is formed for the given coordinates for ABCD, and then find the perimeter and area as an exact value and ro

Helga [31]

Answer:

Part 1) The shape is a trapezoid

Part 2) The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

Part 3) The area is $937.5\ units^2$

Step-by-step explanation:

step 1

Plot the figure to better understand the problem

we have

A(-28,2),B(-21,-22),C(27,-8),D(-4,9)

using a graphing tool

The shape is a trapezoid

see the attached figure

step 2

Find the perimeter

we know that

The perimeter of the trapezoid is equal to

$P=AB+BC+CD+AD$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

we have

A(-28,2),B(-21,-22)

substitute in the formula

$d=\sqrt{(-22-2)^{2}+(-21+28)^{2}}$

$d=\sqrt{(-24)^{2}+(7)^{2}}$

$d=\sqrt{625}$

$d_A_B=25\ units$

Find the distance BC

we have

B(-21,-22),C(27,-8)

substitute in the formula

$d=\sqrt{(-8+22)^{2}+(27+21)^{2}}$

$d=\sqrt{(14)^{2}+(48)^{2}}$

$d=\sqrt{2,500}$

$d_B_C=50\ units$

Find the distance CD

we have

C(27,-8),D(-4,9)

substitute in the formula

$d=\sqrt{(9+8)^{2}+(-4-27)^{2}}$

$d=\sqrt{(17)^{2}+(-31)^{2}}$

$d=\sqrt{1,250}$

$d_C_D=25\sqrt{2}\ units$

Find the distance AD

we have

A(-28,2),D(-4,9)

substitute in the formula

$d=\sqrt{(9-2)^{2}+(-4+28)^{2}}$

$d=\sqrt{(7)^{2}+(24)^{2}}$

$d=\sqrt{625}$

$d_A_D=25\ units$

Find the perimeter

$P=25+50+25\sqrt{2}+25$

$P=(100+25\sqrt{2})\ units$

simplify

$P=25(4+\sqrt{2})\ units$ ----> exact value

$P=135.4\ units$

therefore

The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

step 3

Find the area

The area of trapezoid is equal to

$A=\frac{1}{2}[BC+AD]AB$

substitute the given values

$A=\frac{1}{2}[50+25]25=937.5\ units^2$

4 0

2 years ago

jan, mya, and sara ran a total of 64 miles last week. jan and mya ran the same number of miles. sara ran 8 less miles than jan a

kherson [118]

$x-\ Jan's\ destination\\\\y-\ Mya's \ destination \\\\ z-\ Sara's\ destination\\\\\
x+y+z=64\\
x=y\\
z-8=2x\\\\
x+x+z=64\\
z=2x+8\\\\
2x+2x+8=64\\\\
4x+8=64\\\\
4x=64-8\\\\
4x=56\ \ |:4\\\\x=14\\\\z=2x+8=2*14+8=28+8=36\\\\ Sara\ ran\ 36\ miles.$

5 0

2 years ago

Help and please number the answers accurately thanks a lot!

kvasek [131]

Answer:

I KNOWW THE ANSWER!!

Step-by-step explanation:

7 0

2 years ago