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4 years ago

What is 1/3 of 123 can someone help me

Mathematics

1 answer:

pogonyaev4 years ago

8 0

Answer:

Step-by-step explanation:

Here we will explain how to calculate one third of 123.

One third of 123 is simply one third times 123, which can be written as follows:

One/third x 123

Furthermore, you can convert "one" to "1" and "third" to "3" and then the equation and answer is: 1/3 x 123 = 41

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△JKL has vertices at J(−2, 4), K(1, 6), and L(4, 4). Determine whether △JKL is a right triangle

adelina 88 [10]

Answer:

Not a right triangle

Obtuse isosceles triangle.

Sides: J = 3.606 K = 6 L = 3.606

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3 years ago

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A city hosted a music festival that included three concerts. According to the sales database, 28% of the audience attended the f

Vitek1552 [10]

Answer:

$P(X\cap Y\cap Z)=0.05$

Step-by-step explanation:

From the question we are told that:

Percentage of audience in first concert $P(X)=0.28$

Percentage of audience in second concert $P(Y)=0.42$

Percentage of audience in third concert $P(Z)=0.30$

Audience Percentage at at-least one concert $P(X \cup Y \cup Z)=0.80$

Percentage of audience at first & second concert $P(X \cap Y)=0.10$

Percentage of audience in first & third concert $P(X \cap Z)=0.08$

Percentage of audience in second & third concert $P(Y\cap Z)=0.07$

Generally the equation for probability of attending all concerts $P(X\cap Y\cap Z)$ is mathematically given by

$P(X \cup Y \cup Z)=P(X)+P(Y)+P(Z)-P(X \cap Y)-P(X \cap Z)-P(Y\cap Z)+P(X\cap Y\cap Z)$

$P(X\cap Y\cap Z)=P(X \cup Y \cup Z)-P(X)-P(Y)-P(Z)+P(X \cap Y)+P(X \cap Z)+P(Y\cap Z)$

$P(X\cap Y\cap Z)=0.80-0.28-0.42-0.30+0.10+0.80+0.70$

$P(X\cap Y\cap Z)=0.05$

Therefore the probability that a randomly selected audient attended all the concerts

$P(X\cap Y\cap Z)=0.05$

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3 years ago

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Oksana_A [137]

In 1 hr the bus would have traveled 48.5 miles

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3 years ago

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There are 12 marbles in total in the bowl.
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Out of this, what is the probability that there is exactly 1 blue marble.
There are 5 blue balls but only 1 is selected, 5C1 ways
The rest except blue calls are 7, but only 3 slots are left, 7C3 ways

The probably of exactly 1 blue of 4 marbles is then 5C1*7C3/12C4 = 1050/11,880 = 0.0884 or 8.84%

Hope this helps:) would appericate brainliest thanks

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3 years ago

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BRAINLIEST IF CORRECT

dalvyx [7]

Answer:

Ethan is correct because |7| = 7 and |-3| = 3 so 7 + 3 = 10. Plot 7 on a number line, and move right 3 to get 10 on the line.

Step-by-step explanation:

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