The given expression is:
![\sqrt[5]{64 x^{7} w^{5} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B64%20x%5E%7B7%7D%20%20w%5E%7B5%7D%20%7D%20)
The expression can be simplified as follows:
![\sqrt[5]{64 x^{7} w^{5} } \\ \\ = \sqrt[5]{(2)^{6} x^{7} w^{5} } \\ \\ = \sqrt[5]{(2)^{5}*2* x^{5}* x^{2} * w^{5} } \\ \\ = \sqrt[5]{ (2^{5} x^{5} w^{5} )*2 x^{2} } \\ \\ = \sqrt[5]{(2xw)^{5}*2 x^{2} } \\ \\ =2xw* \sqrt[5]{2x^{2} } ](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B64%20x%5E%7B7%7D%20w%5E%7B5%7D%20%7D%20%5C%5C%20%20%5C%5C%20%0A%3D%20%5Csqrt%5B5%5D%7B%282%29%5E%7B6%7D%20%20x%5E%7B7%7D%20%20w%5E%7B5%7D%20%7D%20%5C%5C%20%20%5C%5C%20%0A%3D%20%5Csqrt%5B5%5D%7B%282%29%5E%7B5%7D%2A2%2A%20x%5E%7B5%7D%2A%20x%5E%7B2%7D%20%2A%20w%5E%7B5%7D%20%20%20%7D%20%20%5C%5C%20%20%5C%5C%20%0A%3D%20%5Csqrt%5B5%5D%7B%20%282%5E%7B5%7D%20%20x%5E%7B5%7D%20%20w%5E%7B5%7D%20%29%2A2%20x%5E%7B2%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%0A%3D%20%5Csqrt%5B5%5D%7B%282xw%29%5E%7B5%7D%2A2%20x%5E%7B2%7D%20%20%7D%20%20%5C%5C%20%20%5C%5C%20%0A%3D2xw%2A%20%5Csqrt%5B5%5D%7B2x%5E%7B2%7D%20%7D%20%0A%20)
The expression can be simplified as follows:
Anyone know how to do this?
2 answers:
You might be interested in
Answer:
x = 10, AB = 57
Step-by-step explanation:
In a trapezoid, the length of the median is one-half the sum of the lengths of the bases. From this, we have: