Answer:
Step-by-step explanation:
We want to determine a 95% confidence interval for the mean total cholesterol level of all males.
Number of sample, n = 355
Mean, u = 185 mg
Standard deviation, s = 16
For a confidence level of 95%, the corresponding z value is 1.96. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean +/- z ×standard deviation/√n
It becomes
185 +/- 1.96 × 16/√355
= 185 +/- 1.96 × 0.849
= 185 +/- 1.66404
The lower end of the confidence interval is 185 - 1.66404 =183.336
The upper end of the confidence interval is 185 + 1.66404 = 186.66
Therefore, with 95% confidence interval, the mean total cholesterol level of all males is between 183.336 mg and 186.66 mg
(7 + i) - (6 - 2i) = 7 + i - 6 + 2i = 1 + 3i
16/25 is 0.64 as a fraction in lowest terms
Answer:
Step-by-step explanation:
Answer:
see explanation
Step-by-step explanation:
(10)
To evaluate f(- 4) substitute x = - 4 into f(x)
f(x) = 7x - 4x + 3 = 3x + 3
f(- 4) = 3(- 4) + 3 = - 12 + 3 = - 9
(11)
To evaluate f(- 2) substitute x = - 2 into f(x)
f(- 2) = 2(- 2)² - 8 = 2(4) - 8 = 8 - 8 = 0
(12)
To evaluate g(- 3) substitute x = - 3 into g(x)
g(- 3) = - 2(- 3)² + 3(- 3) = - 2(9) - 9 = - 18 - 9 = - 27
