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IrinaK [193]
4 years ago
5

Please help thank you

Mathematics
1 answer:
pav-90 [236]4 years ago
4 0
That is true (:

32,178>24151 is correct.

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A car traveling at 35mph follows a/an ____________ pattern.
zheka24 [161]

Answer:

C. Exponential

6 0
3 years ago
3x-24 x+10 what is the value of x
Arisa [49]
3x-24=x+10
3x-x=24+10
2x=34
x=34:2=17
8 0
4 years ago
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Round 299 to the nearest hundred. Enter your answer in the box below.
Troyanec [42]

Answer:

300

Step-by-step explanation:

hundreds  tens  ones

2                   9      9

We look at the tens

It is 5 or higher so we round up the hundreds place

2 becomes 3

300

7 0
3 years ago
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2. 10x - 11 - 4x = 43
Nezavi [6.7K]

Answer:

x=9

Step-by-step explanation:

10x - 11 -4x = 43

6x -11 =43

6x = 54

x=9

8 0
4 years ago
Find the solution of the given initial value problems in explicit form. Determine the interval where the solutions are defined.
natali 33 [55]

Answer:

The solution of the given initial value problems in explicit form is y=x-x^2-2  and the solutions are defined for all real numbers.

Step-by-step explanation:

The given differential equation is

y'=1-2x

It can be written as

\frac{dy}{dx}=1-2x

Use variable separable method to solve this differential equation.

dy=(1-2x)dx

Integrate both the sides.

\int dy=\int (1-2x)dx

y=x-2(\frac{x^2}{2})+C                  [\because \int x^n=\frac{x^{n+1}}{n+1}]

y=x-x^2+C              ... (1)

It is given that y(1) = -2. Substitute x=1 and y=-2 to find the value of C.

-2=1-(1)^2+C

-2=1-1+C

-2=C

The value of C is -2. Substitute C=-2 in equation (1).

y=x-x^2-2

Therefore the solution of the given initial value problems in explicit form is y=x-x^2-2 .

The solution is quadratic function, so it is defined for all real values.

Therefore the solutions are defined for all real numbers.

4 0
3 years ago
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