A ( x + 3 ) < 5x + 15

jarptica [38.1K]

<h3>1.Area of the parallelogram= 288 square units</h3><h3>2.Area of the parallelogram=45 $m^2$ </h3><h3>3.Area of the trapezoid = 34 square in.</h3><h3>4.Area of the trapezoid = 8 square ft</h3><h3>5.Area of the rhombus= 27 square cm</h3><h3>6.Area of the rhombus= 108 square in</h3><h3>7.The area of the desktop is = 1200 square in</h3><h3>8.The area of the rhombus is =84 $cm^2$ </h3><h3>9.Area of the trapezoid = 240 square ft</h3>

Step-by-step explanation:

1.

Base =16 ft and Height = 18 ft

Area of the parallelogram = base × height

=16× 18 square units

= 288 square units

2.

Base = 9 m and height = 5 m

Area of the parallelogram = base × height

=(9×5) $m^2$

=45 $m^2$

3 .

Height = 4 in and parallel sides are 12 in and 5 in

Area of the trapezoid = $\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height$

$=\frac{1}{2} \times (12+5) \times 4$ square in.

= 34 square in.

4.

Height = 2 ft and parallel sides are 2 ft and 6 ft

Area of the trapezoid = $\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height$

$=\frac{1}{2} \times (2+6) \times 2$ square ft

= 8 square ft

5.

Diagonals are 6 cm and 9 cm.

Area of the rhombus $= \frac{1}{2}\times {\textrm{product of diagonals}$

$=\frac{1}{2 } \times 6\times 9$ square cm

= 27 square cm

6. Diagonals are 12 in and 18 in

Area of the rhombus $= \frac{1}{2}\times {\textrm{product of diagonals}$

$=\frac{1}{2 } \times 12\times 18$ square in

= 108 square in

7. Given a desktop in the shape of a parallelogram has a base 30 in. and a height of 40 in

The area of the desktop is = (30 × 40 ) square in

= 1200 square in

8. Given , a rhombus has one diagonal that is 14 cm and other diagonal 12 cm.

The area of the rhombus = $\frac {1}{2} \times 14 \times 12$ $cm^2$

=84 $cm^2$

9.Given , the base of trapezoid are 24 ft and 16 ft and height is 12 ft

Area of the trapezoid = $\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height$

= $\frac{1}{2} \times (24+16) \times 12$ square ft

= 240 square ft

8 0

3 years ago

PLEASE HELP!!! I NEED IT FAST! <br><br> Solve for x

STatiana [176]

540-138-144-107-90=61. answer is 61

4 0

3 years ago

Simplify the expression.<br> (the quantity x to the one-sixth power end quantity to the power of 3.)

Usimov [2.4K]

Answer:

$\sqrt{x}$

Step-by-step explanation:

If we have that worded expression, we can convert it into actual mathematical terms.

x to the one sixth power: $x^{\frac{1}{6}}$

That to the power of 3:

$(x^{\frac{1}{6}})^3$

Using exponent rules, since we have a power to a power, the powers multiply, so:

$x^{\frac{1}{6}\cdot 3}\\\\x^{\frac{3}{6}}\\\\ x^{\frac{1}{2}}$

If we have a number to a fraction power, the denominator becomes the “find the (denominator) root of x.

So:

$x^{\frac{1}{2}} = \sqrt{x}$

Hope this helped!

8 0

3 years ago

Read 2 more answers

What is the area, in square inches, of the isosceles trapezoid below?

Nostrana [21]

Area of a trapezoid: (top + bottom)/2 x height

Area = (6.5 + 15.1)/2 x 5

Area = 21.6/2 x 5

Area = 10.8 x 5

Area = 54 square inches.

3 0

3 years ago

Help pls

PtichkaEL [24]

Answer:

the length is 14 yards and the width is 8 yards

7 0

3 years ago

A ( x + 3 ) < 5x + 15 - x