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blondinia [14]
3 years ago
15

a student tries out for the track and runs 45 seconds. The coach tell her she will have to cut her time 50% to make the team. ho

w fast must she runs to make the team
Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
4 0
She will have to run in 22.5 seconds.

45 - 50% = 22.5
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On a number​ line, suppose point E has a coordinate of -4 ​, and EG = 13. What are the possible coordinates of point​ G?
Ludmilka [50]

Answer:

9 or -17

Step-by-step explanation:

Hello!

The distance can be positive or negative, as we are just counting the number of units they are apart.

To find the possible coordinates for G, we can add or subtract 13 from -4 to find the possible coordinates for G.

<h3>Find G</h3>
  • -4 + 13 = G1
    -4 - 13 = G2
  • 9 = G1
    -17 = G2

The possible coordinates of G are 9 or -17.

7 0
1 year ago
Add the following 2 wholes and 3/8 plus 3 wholes and 3/7
FinnZ [79.3K]

Answer:

325/56

is the answer

6 0
3 years ago
Read 2 more answers
Please write the answer​
Travka [436]

\sf \dfrac{3^x - 5 \times 3^{(x-2)}}{3^{(x-3)}} \\ \\ \longrightarrow \sf \dfrac{ {3}^{x} }{ {3}^{(x - 3)}} - \frac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)}  \\ \\ \longrightarrow \sf {3}^{[x - (x - 3)]} - \dfrac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ {3}^{(x - 3)} } \times \dfrac{ {3}^{x}}{9} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ \bigg(\dfrac{ {3}^{x} }{ {3}^{3} }\bigg) } \times \dfrac{ {3}^{x}}{9}\\ \\ \longrightarrow \sf {3}^{3} - \dfrac{ ({3}^{3})( 5)}{ {3}^{x} } \times \dfrac{ {3}^{x}}{9}\\ \\ \sf \longrightarrow {3}^{3} - (5 \times 3) \\  \\ \longrightarrow \sf \: 27 - 15 \\  \\ \longrightarrow \leadsto{\underline{\boxed{\sf{ \pink{ 12}}}}}

6 0
3 years ago
This exercise involves the formula for the area of a circular sector. The area of a circle is 700 m2. Find the area of a sector
mezya [45]

Answer:

334.4 m²

Step-by-step explanation:

The formula for the area of a sector is given as:

1/2 × r² × θ

Where θ = Central angle

Area of a Circle = 700 m²

The formula for the area of a circle = πr²

r = Radius of a circle

r² = Area / π

r = √Area / π

r = √700/π

r = 14.927053304 m

Approximately, r = 14.93 m

Therefore, the area of the sector

= 1/2 × r² × θ

= 1/2 × 14.93² × 3 rad

= 334.35735 m²

Approximately, Area of the sector = 334.4 m²

4 0
3 years ago
Use long division to calculate 276 ÷ 15
Alja [10]

Answer:

18.4

Step-by-step explanation:

7 0
3 years ago
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