A) See picture for the table.
To make the table, multiply 47774 by 1.5% to get total that have diabetes and multiply 5855 by 2.5% to get total unemployed that have it, then using subtraction fill in the other squares of the table.
B)
Hypothesis:
H0: No association between employment and diabetes.
H1: Association between the two
Using a graphing calculator or Excel, run a chi-test.
Chi squared equals 31.844 with 1 degrees of freedom.
The two-tailed P value is less than 0.0001
With this information we can reject the null hypothesis and conclude there is an association between diabetes and employment.
C)
Although there is a statistical significance, there really is no practical significance between an incidence rate of 1.5 or 2.5%
Answer:
o/3 or 1/1
Step-by-step explanation:
we have that
*-------------------------*--------------------------------*
E F G
EF=2x-12
FG= 3x-15
EG=23
we know that
EF + FG = EG
so
[2x - 12] + [3x - 15] = 23 simplify
5x - 27 = 23 add 27 to both sides
5x = 50 divide both sides by 5
x = 10
EF=2x-12-------> EF=2*10-12-------> EF=8
FG= 3x-15------> FG=3*10-15------> FG=15
therefore
the answer part a) is
the value of x is 10
the answer part b) is
the value of EF is 8
the answer part c) is
the value of FG is 15
Answer:
Step-by-step explanation:
Total number of people = 130
Number of people who use the gym = 73
Number of people who use the pool = 62
Number of people who use the track = 58
Number of people who use the gym and the pool = 22
Number of people who use the pool and the track = 29
Number of people who use the gym and the track = 25
Number of people who use all three facilities = 11
Total number of people who use at least two facilities = 22 + 29 + 25 + 11 = 87
The probability that the randomly selected person uses all three facilities = number of those who use all three facilities ÷ total number of people who use at least two facilities.
==> 11 ÷ 87
==>
7 days a week
4x7=28
About 4 weeks each month
28x4=112
The answer should be 112 hours. I hope this helped
