The center of rotation is point P. Which describes the rotation of ΔABC to form ΔA'B'C'?
1 answer:
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Use quadratic formula since we can't factor
for 0=ax²+bx+c
so, for
0=1x²-6x-4
a=1
b=-6
c=-4
the solutions are x=3+√13 and x=3-√13
or aprox
x≈6.61 and x≈-0.61
for 0=ax²+bx+c
so, for
0=1x²-6x-4
a=1
b=-6
c=-4
the solutions are x=3+√13 and x=3-√13
or aprox
x≈6.61 and x≈-0.61