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soldier1979 [14.2K]
3 years ago
6

Explain how you would test the presence of oxygen and hydrogen gases. ​

Chemistry
1 answer:
Vedmedyk [2.9K]3 years ago
5 0
Place a burning splint near the opening of a test tube. If a popping noise occurs, it's probably hydrogen. Place a glowing splint in the test tube, and if it reignites, it could be oxygen. Place a burning splint into a test tube, and if it goes out, it could be carbon dioxide.
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Is the equation above balanced or unbalanced? Explain? Worth 55 points.
Paul [167]

Answer:

For me, it is balanced

Explanation:

Because the amount of element Zn reaction is equal the production. Also as the amount of Hydrogen and Chloride in the reaction and the production are equal.

8 0
3 years ago
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If I have 6 moles of a gas at a pressure of 3.4 atm and a volume of 10 liters, what
ch4aika [34]

Answer:

The temperature is 69.05 K.  

Explanation:

We have,

Number of moles are 6

Pressure is 3.4 atm and a volume of 10 liters.

It is required to find the temperature. It can be calculated using gas law equation. It says that,

PV=nRT

P is pressure

V is volume

n is number of moles

R is gas constant, R=0.082057\ L-atm/mol-K

T is temperature                

Plugging all the values we get :

T=\dfrac{PV}{nR}\\\\T=\dfrac{3.4\times 10}{6\times 0.082057}\\\\T=69.05\ K

So, the temperature is 69.05 K.  

8 0
3 years ago
What is the function of this instrument?
chubhunter [2.5K]
To measure weight of a item
7 0
3 years ago
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6 0
3 years ago
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What mass of barium sulfate (233 g/mol) is produced when 125 mL of a 0.150 M solution of barium chloride is mixed with 125 mL of
Rzqust [24]

Answer:

4.37 g of barium sulphate

Explanation:

The reaction equation is;

3BaCl2(aq) + Fe2(SO4)3(aq) ---->3 BaSO4(s) + 2FeCl3(aq)

From the question, the number of moles of both barium chloride and FeSO4 = 125/1000 L × 0.150 M = 0.01875 moles

To find the limiting reactant;

3 moles of barium chloride yields 3 moles of barium sulphate

0.01875 moles of barium chloride yields 3 × 0.01875 moles/3 = 0.01875 moles of barium sulphate

1 mole of iron III sulphate yields 3 moles of barium sulphate

0.01875 molesof iron III sulphate yields 0.01875 moles ×3/1 = 0.05625 moles of barium sulphate

Hence,barium chloride is the limiting reactant

Amount of barium sulphate produced = 0.01875 moles × 233 g/mol = 4.37 g of barium sulphate

4 0
2 years ago
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