Explain how you would test the presence of oxygen and hydrogen gases.
1 answer:
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Answer:
3.96 × 10⁻³ mol Pb
Explanation:
Step 1: Find molar mass
Pb (Lead) - 207.2 g/mol
Step 2: Use Dimensional Analysis
= 0.003962 mol Pb
Step 3: Simplify
We have 3 sig figs
0.003962 mol Pb ≈ 0.00396 mol Pb
0.00396 mol Pb = 3.96 × 10⁻³ mol Pb
Answer : 70.906 grams of chlorine reacted with hydrogen
Explanation :
Step 1 : Write balanced chemical equation.
The balanced chemical equation for the reaction between hydrogen and chlorine gas is given below.
Step 2 : Find moles of H₂ gas.
The moles of H₂ can be found as
We have 2.0200 g of H₂ and molar mass of H₂ is 2.02 g/mol.
Let us plug in these values to find moles of H₂.
We have 1 mol of H₂.
Step 3 : Find moles of Cl₂ using mole ratio.
The mole ratio of H₂ and Cl₂ is 1 : 1.
The moles of Cl₂ can be calculated as
Step 4 : Find grams of Cl₂.
Molar mass of Cl₂ gas is 70.096 g/mol
Mass of Cl₂ =
We have 70.906 grams of Cl₂