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SVETLANKA909090 [29]
3 years ago
8

The most laterally placed of the three erector spinae components, the ___________ group, is composed of three parts: cervical, t

horacic, and lumbar.
Chemistry
2 answers:
BabaBlast [244]3 years ago
4 0

Answer:

Iliocostalis group.

Explanation:

Iliocostalis is a muscle located at the back of the body of a human, it is one of the three columns of the individual muscles that are composed of fascicles that are laterally placed. This group of muscles helps in bending to the side, bending backwards and in the rotation of the spinal column. The cervical part of iliocostalis is the upper part that extends from the upper ribs to the side projections of the cervical vertebrae in the neck, the thoracic part is the middle part of the iliocostalis that extends from the lower to the upper ribs while the lumbar part of iliocostalis is the lower part that extends from the upper part of the hipbone to the lower ribs.

schepotkina [342]3 years ago
3 0

Answer:iliocostalis group

Explanation:

It's located on the back of the human body and here are some of what this group do;

• Acting together, muscles of each consistuent region extend and maintain erect posture of vertebral column in their respective region.

• Acting singly, laterally flex vertebral column in their region.

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What volume of a 2.25 M sodium chloride solution will contain 4.58 moles of sodium chloride
Rzqust [24]

Answer:

Option E. 2.04 L

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6 0
3 years ago
Consider the reaction:
goldfiish [28.3K]

Answer:

K = Ka/Kb

Explanation:

P(s) + (3/2) Cl₂(g) <-------> PCl₃(g) K = ?

P(s) + (5/2) Cl₂(g) <--------> PCl₅(g) Ka

PCl₃(g) + Cl₂(g) <---------> PCl₅(g) Kb

K = [PCl₃]/ ([P] [Cl₂]⁽³'²⁾)

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From the Ka equation,

[PCl₅] = Ka ([P] [Cl₂]⁽⁵'²⁾)

From the Kb equation

[PCl₅] = Kb ([PCl₃] [Cl₂])

Equating them

Ka ([P] [Cl₂]⁽⁵'²⁾) = Kb ([PCl₃] [Cl₂])

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Comparing this with the equation for the overall equilibrium constant

K = Ka/Kb

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3 years ago
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