I don't think he will have enough flour I guess, but from my perspective when I divided and multiplied and whatnot I didn't get a whole number. I got mostly decimals, so I think there won't be enough flour.

8 0

3 years ago

Read 2 more answers

Please help

katrin2010 [14]

$\dfrac{n^2+3n+2}{n^2+6n+8}-\dfrac{2n}{n+4}\\\\=\dfrac{n^2+2n+n+2}{n^2+4n+2n+8}-\dfrac{2n}{n+4}\\\\=\dfrac{n(n+2)+1(n+2)}{n(n+4)+2(n+4)}-\dfrac{2n}{n+4}\\\\=\dfrac{(n+2)(n+1)}{(n+2)(n+4)}-\dfrac{2n}{n+4}\\\\=\dfrac{n+1}{n+4}-\dfrac{2n}{n+4}=\dfrac{n+1-2n}{n+4}=\dfrac{1-n}{n+4}$

$Answer:\ \boxed{B.\ \dfrac{1-n}{n+4}}$

7 0

3 years ago

The following are the weights, in pounds, of some dogs at a kennel: 36, 45, 29, 39, 51, 49

MAXImum [283]

What is the question...??

5 0

3 years ago

HELP

kati45 [8]

Slope: 1/5

Y-intercept: 0

Equation: Y= 5x

5 0

3 years ago